CODEWITHSUNDEEP
cprintf
jellies
jellies

Reputation: 639

Is there a way to not specify a specifier in printf?

The people over at cplusplus.com give the reference for printf as so:
printf("%[flags][width][.precision][length]specifier", "Message");
but if I wanted to to prepend some spaces, I would have to use %[number of spaces]s, "" ...etc is there a clearer way to prepend spaces, without clunkily prepending empty strings?

Upvotes: 1

Views: 74

Answers (2)

chux
chux

Reputation: 153367

Use * to specify the total width. No prepended empty strings.

const char *message = "Message";
int number_of_spaces = 3;
int width = number_of_spaces + strlen(message);

printf("<%*s>\n", width, message);

Output

<   Message>

Upvotes: 3

R Sahu
R Sahu

Reputation: 206577

You can use printf("%15s", ""); to print just 15 spaces.

You can use printf("%15s%d\n", "", number); to print a number with 15 spaces prepended to the output.

Upvotes: 1

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