CODEWITHSUNDEEP
pythondirectory
jredd
jredd

Reputation: 73

Python - create folder with multiple subfolders

I need to create a list of folders each with multiple subfolders that are not nested. I have used

os.makedirs('folder/subfolder')

to create a folder and a subfolder but I can only make multiple nested folders work:

os.makedirs('folder/subfolder1/subfolder2/subfolder3')

where sub3 is nested in sub2 which is nested in sub1. What I want is for sub 1, 2 and 3 all to be nested in 'folder' together (3 folders inside 1 folder). I tried

os.makedirs('folder/(subfolder1, subfolder2)')

but that just creates a folder titled "(subfolder1, subfolder2)" Does anyone know the correct syntax for this? Is it even possible with the makedirs function?

Upvotes: 7

Views: 35099

Answers (3)

Anmol Singh Jaggi
Anmol Singh Jaggi

Reputation: 8576

Use a loop:

for i in range(1,100):
    os.makedirs(os.path.join('folder', 'subfolder' + str(i)))

Or, if you have the names in a list:

subfolder_names = []
for subfolder_name in subfolder_names:
    os.makedirs(os.path.join('folder', subfolder_name))

p.s.

In case to ignore already-exist folder

os.makedirs('/path/to/dir', exist_ok=True)

Upvotes: 16

tuned
tuned

Reputation: 1125

You can loop using a list comprehension, create the directory at each iteration using os.mkdir and assigning it a name that is the result of joining the base path to a given directory name.

import os

[os.mkdir(os.path.join("/folder", "subdir{}".format(i))) for i in range(100)]

Upvotes: 2

zondo
zondo

Reputation: 20336

You can't do it in one call like that. Just put one call after another:

os.makedirs("folder/subfolder1")
os.makedir("folder/subfolder2")

Upvotes: 2

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