CODEWITHSUNDEEP
phphtml
Sevengames Xoom
Sevengames Xoom

Reputation: 322

Can't get the last part of url

I'm trying to get the last part of this url string: national/italy/serie-a/20152016/s11663/

my goal is get: s11663 this is my code:

$path = parse_url("national/italy/serie-a/20152016/s11663/", PHP_URL_PATH);
$pathFragments = explode('/', $path);
$end = end($pathFragments);
var_dump($end);

but I get:

string(0) ""

what I did wrong?

Upvotes: 3

Views: 488

Answers (3)

Ikari
Ikari

Reputation: 3236

I your $path the string contains a / at the end so, when you explode that, the last / also gets counted and the last fragment contains nothing because there is nothing after the last /, So just remove the /.

$path = parse_url("national/italy/serie-a/20152016/s11663", PHP_URL_PATH);
$pathFragments = explode('/', $path);
$end = end($pathFragments);
var_dump($end);

Or if you cannot remove that last /, then just substr the string:

$url = "national/italy/serie-a/20152016/s11663/";
$url = substr($url, 0, strlen($url) - 1);
$path = parse_url($url, PHP_URL_PATH);
$pathFragments = explode('/', $path);
$end = end($pathFragments);
var_dump($end);

Hope it helps you!

Update

In the last example it just substr's the last char get cut, no matter what char, so, what you can do is just as suggested by @firstone's comment, use rather than $url = substr($url, 0, strlen($url) - 1);, is:

$url = rtrim($url, "/");

OR, This:

if($url[strlen($url) - 1] == "/") {
    $url = substr($url, 0, strlen($url) - 1);
} else {
    // Let the url be as it is.....
}

Upvotes: 5

FirstOne
FirstOne

Reputation: 6217

Because you have a trailing / in the end, you have to get the second last:

$path = parse_url("national/italy/serie-a/20152016/s11663/", PHP_URL_PATH);
$pathFragments = explode('/', $path);
array_pop($pathFragments); // remove last (empty value)
$end = end($pathFragments);
var_dump($end);

Take a look at the output of $pathFragments on your question:

Array
(
    [0] => national
    [1] => italy
    [2] => serie-a
    [3] => 20152016
    [4] => s11663
    [5] => 
)

This code will work for strings ending with and without /:

$path = parse_url("national/italy/serie-a/20152016/s11663", PHP_URL_PATH);
$pathFragmenst = (substr($path, -1) == '/') ? 
    $pathFragments = explode('/', $path, -1) :
    $pathFragments = explode('/', $path);

$end = end($pathFragments);
var_dump($end);

Output for ../s11663/: https://3v4l.org/BWjkd

string(6) "s11663"

Output for ../s11663: https://3v4l.org/H7fP9

string(6) "s11663"

Notes:

1 - This code:

$pathFragmenst = (substr($path, -1) == '/') ? 
    $pathFragments = explode('/', $path, -1) :
    $pathFragments = explode('/', $path);

Is short for this:

if(substr($path, -1) == '/'){
    $pathFragments = explode('/', $path, -1);
}else{
    $pathFragments = explode('/', $path);
}

2 - I don't know if that string is the result of the url_parse, or you are really trying to parse it, but

var_dump(parse_url("national/italy/serie-a/20152016/s11663", PHP_URL_PATH));

will output

string(38) "national/italy/serie-a/20152016/s11663"

, so there is not need to parse_url it - unless you are trying to parse something like:

http://example.com/national/italy/serie-a/20152016/s11663/
^^^^^^^^^^^^^^^^^^^

I left it as is in case you are going to use the complete url...

Upvotes: 3

maxhb
maxhb

Reputation: 8865

When you do explode('/', $path); the last element of the result array is empty because the last item will be the part after the last "/".

Either use one of the proposed solutions or switch to using preg_match():

$end = '';
$path = parse_url("national/italy/serie-a/20152016/s11663/", PHP_URL_PATH);

if(preg_match('#/([^/]+)/$#', $path, $matches)) {
  $end = $matches[1];
}

var_dump($end);

Upvotes: 2

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