CODEWITHSUNDEEP
iphonensdecimalnumber
james_womack
james_womack

Reputation: 10316

Raise an NSDecimalNumber to a negative power

I need an equivalent to C's pow() function that will work with NSDecimalNumbers. With pow you can use negative numbers e.g. pow(1514,-1234), with NSDecimal's decimalNumberByRaisingToPower: method, you are forced to use an NSUInteger which seems to require a positive value.

I'd like to be able to do something like this:

[decimalNumber decimalNumberByRaisingToPower:-217.089218];

or

[decimalNumber decimalNumberByMultiplyingByPowerOf10:-217];

without crashing from overflow or underflow exceptions.

Upvotes: 3

Views: 1286

Answers (3)

Fred Fnord
Fred Fnord

Reputation: 11

Incidentally, you appear to be correct about decimalNumberByRaisingToPower, but, from the Apple docs:

(NSDecimalNumber *)decimalNumberByMultiplyingByPowerOf10:(short)power

That's not unsigned.

Upvotes: 1

kennytm
kennytm

Reputation: 523784

Mathematically, a^(-b) == 1/(a^b). Therefore, if you just need to raise to a negative integral power,

decimalNumber = [decimalNumber decimalNumberByRaisingToPower:1234];
decimalNumber = [[NSDecimalNumber one] decimalNumberByDividingBy:decimalNumber];

For non-integral powers, there's no way except (1) implement the pow() algorithm yourself or by 3rd party libraries, or (2) performing the calculation in floating point (thus losing precisions).

Upvotes: 4

cooltechnomax
cooltechnomax

Reputation: 701

You can first convert decimalNumber to its doubleValue and then just call the pow function of C++. I haven't tried it but I think it should work. Refer: Calling Objective-C method from C++ method? for mixing c++ and objective c.

Upvotes: 0

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