Reputation: 117
I need to write a method that adds the two last elements of two arrays together and add the sum on another array. But if the two elements are more than 10, then I would need to carry that number to the next array.
This program should be similar to what an odometer does.
Here is my sample code.
int [] sum(int []number1, int []number2)
{
int [] total;
int carry = 0;
for ( int k = numbers1 - 1; k >= 0; k++)
{
sum = number1[k] + number2[k] + carry;
carry = sum/10;
total[k] = sum
}
return total;
}
An example output would be:
0 1 2 3 4
0 8 9 9 9
4 5 7 0 3
5 4 7 0 2
So the top array is just a visual aid that tells where the position for the number is. The program is suppose to add the next two arrays together. i.e. 9 + 3 = 12 Since 12 is above 9, it carries over the 10 to the next set of arrays, that is why the third array only has a 2 in its place, and that is why the next array is 9 + 0 = 0; because the 10 was carried over.
I am not sure why my code won't work. I don't get the right numbers. Could anyone give any hints or solution to the problem?
-Thanks
Upvotes: 0
Views: 1241
Reputation: 3151
I assume numbers1
is the number of elements in the array.
In this case it should be k--
instead of k++
because you are starting from the last element and moving backword.
Upvotes: 1