CODEWITHSUNDEEP
javascript
Mohamed Hegazy
Mohamed Hegazy

Reputation: 273

how can I chop letters of a string into smaller chunks of fixed lengths in JavaScript?

Thanks in advance for taking the time to read. I am a total beginner and I know this might sound one of those "help me understand this" questions but I'm sorry if that was the case and I'll try to be specific as much as I can.

Basically I need to create a function to chop strings into smaller strings of input length, I have tried array methods but for some reason I keep getting an empty array. So that the if the input string is "hell" and the input length is 2 the output would be ["he","ll]

Also, in relevance to this problem, I was wondering if you can set a for loop condition x.length<=0.

Here is my code:

function chop(a, b) { 
    // a = "hell"
    // b = 2

    var ans = [];
    var x = a.split(""); // [h,e,l,l]

    for (var i = 0; i<=(x.length/b); i++) { 
        // condition i<=2
        // I was also wondering how can set the condition to be x.length <= 0

        x  = x.slice(0,(b-1));  // x = "he"
        ans.push(x); // ans = ["he", ]
        x = x.splice(0,b); // x = [l,l]

    }

    console.log(ans);

}

Upvotes: 1

Views: 46

Answers (2)

Oriol
Oriol

Reputation: 288020

It's simple if you use regular expressions:

"hello".match(/.{1,2}/g) || []; // ["he", "ll", "o"]

However, if you don't know the value of the second parameter beforehand, it's a bit more dirty:

function chop(a, b) {
  return a.match(new RegExp('.{1,'+b+'}','g')) || [];
}
chop("hello", 2); // ["he", "ll", "o"]

In that case, it would be a good idea to sanitize b before inserting it in the regex.

Upvotes: 2

The Process
The Process

Reputation: 5953

You can do it like this:

function chop(a, b) {

  var ans = [];

  for (var i = 0; i < a.length; i += b) {
    ans.push(a.substring(i, i + b));
  }
  console.log(ans);   
}

chop("hello", 2);  //logs ["he", "ll", "o"]

Upvotes: 2

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