Reputation: 62464
How to force my C# Winforms program run as administrator on any computer ? and any kind of OS ?
I need code solution (any sample code will be excellent)
Thanks in advance
Upvotes: 37
Views: 65946
Reputation: 415
1-Create an Application Manifest:
In order to run your application with administrative privileges, you need to create an application manifest file. This XML file will inform the operating system that your application requires elevated privileges.
Right-click on your project in the Solution Explorer.
List item Add > New Item > Application Manifest File.
2- Edit the Application Manifest:
Open the newly created app.manifest file. You'll find a commented section labeled requestedExecutionLevel.
Uncomment this section and set the level attribute to "requireAdministrator":
<trustInfo xmlns="urn:schemas-microsoft-com:asm.v2">
<security>
<requestedPrivileges xmlns="urn:schemas-microsoft-com:asm.v3">
<requestedExecutionLevel level="requireAdministrator" uiAccess="false" />
</requestedPrivileges>
</security>
3-Build and Run.
Upvotes: -1
Reputation: 1
I do not think you can force an application to run in Administrative mode. If you can then hackers can fully control your pc
Upvotes: 0
Reputation: 547
The obvious answer is to add a manifest file to the C# project and add the following line:
<requestedExecutionLevel level="requireAdministrator" uiAccess="false" />
But, a rather unorthodox approach can also be taken. We know that registry access requires administrator privileges. So, if you have a function that contains a registry write access, the function will throw a System.Security.SecurityException
if you don't run the program as an administrator. It is implied that you have to call this function at the beginning of the program. If this exception is thrown, you can inform the user to run the program as an administrator and close the program.
public void enforceAdminPrivilegesWorkaround()
{
RegistryKey rk;
string registryPath = @"SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon\";
try
{
if(Environment.Is64BitOperatingSystem)
{
rk = RegistryKey.OpenBaseKey(Microsoft.Win32.RegistryHive.LocalMachine, RegistryView.Registry64);
}
else
{
rk = RegistryKey.OpenBaseKey(Microsoft.Win32.RegistryHive.LocalMachine, RegistryView.Registry32);
}
rk = rk.OpenSubKey(registryPath, true);
}
catch(System.Security.SecurityException ex)
{
MessageBox.Show("Please run as administrator");
System.Environment.Exit(1);
}
catch(Exception e)
{
MessageBox.Show(e.Message);
}
}
Here, the true
in line rk = rk.OpenSubKey(registryPath, true)
tells the program that it needs write access to the registry.
Upvotes: 2
Reputation: 10747
Here is the sample code to run your application as admin.
ProcessStartInfo proc = new ProcessStartInfo();
proc.UseShellExecute = true;
proc.WorkingDirectory = Environment.CurrentDirectory;
proc.FileName = Application.ExecutablePath;
proc.Verb = "runas";
try
{
Process.Start(proc);
}
catch
{
// The user refused the elevation.
// Do nothing and return directly ...
return;
}
Application.Exit(); // Quit itself
Set the ProcessStartInfo.Verb to “runas” will let it run as admin. Here is related FAQ
Upvotes: 12
Reputation: 13696
You can embed this manifest into your application.
<?xml version="1.0" encoding="utf-8" ?>
<asmv1:assembly manifestVersion="1.0" xmlns="urn:schemas-microsoft-com:asm.v1" xmlns:asmv1="urn:schemas-microsoft-com:asm.v1" xmlns:asmv2="urn:schemas-microsoft-com:asm.v2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<assemblyIdentity version="1.0.0.0" name="MyApplication" />
<trustInfo xmlns="urn:schemas-microsoft-com:asm.v2">
<security>
<requestedPrivileges xmlns="urn:schemas-microsoft-com:asm.v3">
<requestedExecutionLevel level="requireAdministrator" uiAccess="false" />
</requestedPrivileges>
</security>
</trustInfo>
</asmv1:assembly>
Upvotes: 64
Reputation: 2992
It needs the Manifest file. Just place a manifest file and choose AsInvoker or AsAdministrator.
If you can access process you might use proc.Verb = "runas";
Check this : http://social.msdn.microsoft.com/Forums/en-US/winforms/thread/db6647a3-85ca-4dc4-b661-fbbd36bd561f
Upvotes: 1