Reputation: 590
I am writing a Java program to read data from excel sheet (having XLSX extension) using Apache POI library. I am able to iterate through all the cells and get all the values. But I am unable to get a specific cell value, say E10. Is there any way to do this?
Please see the code below that I used for iterating through the cells.
package application;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.Iterator;
import org.apache.poi.hssf.usermodel.HSSFCell;
import org.apache.poi.hssf.usermodel.HSSFRow;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;
import org.apache.poi.xssf.usermodel.XSSFCell;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
public class ReadFromXLSX {
public static void readXLSXFile() throws IOException
{
InputStream ExcelFileToRead = new FileInputStream("C:\\Test.xlsx");
XSSFWorkbook wb = new XSSFWorkbook(ExcelFileToRead);
XSSFWorkbook test = new XSSFWorkbook();
XSSFSheet sheet = wb.getSheetAt(0);
XSSFRow row;
XSSFCell cell;
Iterator rows = sheet.rowIterator();
while (rows.hasNext())
{
row=(XSSFRow) rows.next();
Iterator cells = row.cellIterator();
while (cells.hasNext())
{
cell=(XSSFCell) cells.next();
if (cell.getCellType() == XSSFCell.CELL_TYPE_STRING)
{
System.out.print(cell.getStringCellValue()+" ");
}
else if(cell.getCellType() == XSSFCell.CELL_TYPE_NUMERIC)
{
System.out.print(cell.getNumericCellValue()+" ");
}
else
{
}
}
System.out.println();
}
}
}
Upvotes: 13
Views: 99323
Reputation: 107
Just version-up the getCell
method
public XSSFCell getCell(String cellName){
Pattern r = Pattern.compile("^([A-Z]+)([0-9]+)$");
Matcher m = r.matcher(cellName);
XSSFWorkbook wb = new XSSFWorkbook();
if(m.matches()) {
String columnName = m.group(1);
int rowNumber = Integer.parseInt(m.group(2));
if(rowNumber > 0) {
return wb.getSheetAt(0).getRow(rowNumber-1).getCell(CellReference.convertColStringToIndex(columnName));
}
}
return null;
}
Now you can get the cell easily by this line
getCell("E10")
Upvotes: 2
Reputation: 11
public class XmlFileRead {
public static void main(String[] args) throws IOException {
FileInputStream fi = new FileInputStream("abc.xls");
ArrayList<EmployeeVo> al = new ArrayList<>();
EmployeeVo evo = null;
Scanner scanner = null;
Workbook wb = new XSSFWorkbook(fi);
Sheet sh = wb.getSheet("Sheet0");
int starRow = sh.getFirstRowNum();
int endRow = sh.getLastRowNum();
for (int i = starRow + 1; i < endRow; i++) {
scanner = new Scanner(System.in);
evo = new EmployeeVo();
Cell c = wb.getSheetAt(0).getRow(i).getCell(1);
evo.setEmployeeId((int) c.getNumericCellValue());
Cell c2 = wb.getSheetAt(0).getRow(i).getCell(2);
evo.setEmployeeName(c2.toString());
// add to collection
al.add(evo);
} // for
al.forEach(i -> {
System.out.println(i.getEmployeeId() + " " + i.getEmployeeName());
});
}
}
Upvotes: 1
Reputation: 590
To get a value from a specific cell in excel you can use the below code line.
wb.getSheetAt(0).getRow(1).getCell(1);
Upvotes: 3
Reputation: 16641
For example, to get E10 of the first worksheet:
wb.getSheetAt(0).getRow(9).getCell(4);
Note: subtract one because the indices are null-based.
You can also use this convenience method to map E to 4.
wb.getSheetAt(0).getRow(9).getCell(CellReference.convertColStringToIndex("E"));
Upvotes: 31
Reputation: 693
XSSFSheet has the method getRow(int rownum) It returns the logical row ( 0-based). If you ask for a row that is not defined you get a null. This is to say row 4 represents the fifth row on a sheet.
Once you get the row, you can call getCell(int cellnum) method of XSSFRow object. It returns the cell at the given (0 based) index.
Upvotes: 2