CODEWITHSUNDEEP
phpdatestrtotime
jerrygarciuh
jerrygarciuh

Reputation: 21988

Unexpected date outcome for strtotime "-1 month"

I was working with a set of statistics for which I need to specify the start of a preceding month given any start date when I found some dates yielded unexpected results:

$theday = '2015-12-31';
for ($i = 1; $i < 6; $i++) {
    echo "minus $i month = " . date('Y-m', strtotime ("-$i month" , strtotime ( $theday )) ) . '-01' . "\n";
}

Output:

minus 1 month = 2015-12-01
minus 2 month = 2015-10-01
minus 3 month = 2015-10-01
minus 4 month = 2015-08-01
minus 5 month = 2015-07-01

What did I do incorrectly there? What is the correct way to get the year and month for the month preceding date X?

Upvotes: 0

Views: 196

Answers (1)

choult
choult

Reputation: 296

According to https://derickrethans.nl/obtaining-the-next-month-in-php.html, you can write "first day of -x month". The following code:

$theday = '2015-12-02';
for ($i = 1; $i < 6; $i++) {
    echo "minus $i month = " . date('Y-m-d', strtotime ("first day of -$i month" , strtotime ( $theday )) ) . "\n";
}

results in:

minus 1 month = 2015-11-01
minus 2 month = 2015-10-01
minus 3 month = 2015-09-01
minus 4 month = 2015-08-01
minus 5 month = 2015-07-01

Upvotes: 1

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