CODEWITHSUNDEEP
javajunithamcrest
Charles H
Charles H

Reputation: 645

How to use hamcrest contains to compare 2 lists?

Why does this test fail? I know contains works when you pass in individual strings separated by commas but I wanted to see if it's possible to just pass in an entire list of strings instead. I just want to make sure that list 1 contains all of the contents of list 2.

@Test
public void testContains() {
    String expected1 = "hello";
    String expected2 = "goodbye";
    List<String> expectedStrings = new ArrayList<>();
    expectedStrings.add(expected1);
    expectedStrings.add(expected2);
    List<String> actualStrings = new ArrayList<>();
    actualStrings.add(expected1);
    actualStrings.add(expected2);
    assertThat(actualStrings, contains(expectedStrings));
}

Is it considered acceptable to use this assertion instead?

assertThat(actualStrings, is(expectedStrings));

Upvotes: 3

Views: 6103

Answers (2)

lanoxx
lanoxx

Reputation: 13081

If you want to apply a matcher for each item in a list you can use the everyItem matcher, like so:

everyItem(not(isEmptyOrNullString()))

Upvotes: 0

eee
eee

Reputation: 3488

There is no overloaded contains method which takes a list of expected values.

In the statement assertThat(actualStrings, contains(expectedStrings)) the following method (in the Matchers class) is called:

<E> org.hamcrest.Matcher<java.lang.Iterable<? extends E>> contains(E... items)

Basically you are saying that you expect a list with one element and this element is expectedStrings but in fact it is expected1 (E is of type List<String> and not String). To verify add the following to the test which should then pass:

List<List<String>> listOfactualStrings = new ArrayList<>();
listOfactualStrings.add(actualStrings);
assertThat(listOfactualStrings, contains(expectedStrings));

To make the assertion work you have to convert the list to an array: 

assertThat(actualStrings, contains(expectedStrings.toArray()));

Upvotes: 2

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