CODEWITHSUNDEEP
c++loops
Eddie White
Eddie White

Reputation: 327

Only printing a line after the for loop is done (C++)

So I'm having trouble figuring out how to make this piece of code cout the message after the for loop is done. I keeps doing it after every loop. I have multiple for loops checking if a function is increasing/decreasing/non-decreasing/non-increasing. I'm only going to post the increasing one because they're all having the same problem.

I've tried it this way:

for(i=0; i<n; i++)
    {
            if(val[i] < val[i+1])
            {
                 cout << "Function is increasing!" << endl;
            }

    }

And with a counter but I'm pretty sure I used the counter wrong.

Upvotes: 0

Views: 559

Answers (2)

user6067118
user6067118

Reputation:

Use a simple state machine: check that all points verify your condition. If they do, print something.

bool increasing = true;
for (i=0 ; i<n ; i++)
{
    increasing &= val[i] < val[i+1];
}
if (increasing)
{
    std::cout << "Function is increasing!\n";
}

Upvotes: 2

Ben D
Ben D

Reputation: 475

You could juste create a variable to save the state of the function:

enum State {
Increasing,
Decreasing,
NonDecreasing,
NonIncreasing
} state;

and set it correctly in your loop

for(i=0; i<n; i++)
{
        if(val[i] < val[i+1])
        {
             state = State::Increasing;
        }

}

switch(state) {
  case Increasing:
    std::cerr << "Increasing" << std::endl;
    break;
  case Decreasing:
    ...
}

Upvotes: 1

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