dokgu
dokgu

Reputation: 6040

Jquery Clone and Update All ids

I want to clone a div using it's id with many elements inside it which also has their own id that I want to change after cloning.

Consider this HTML structure:

<div id='wrapper1'>
  <p id='test1'>Hello</p>
  <p id='my-awesome-id1'></p>
</div>

I found this on SO but it only changes the id of the main element you cloned and not the children.

Is there a way I could do it so that I could update all of the 1 into 2 and so on?

Upvotes: 0

Views: 1643

Answers (2)

user162097
user162097

Reputation: 1258

You can use a function like this:

function changeIdNumberOnElementAndChildren(element, newIdNumber) {
    var $element = $(element),
        $elementChildren = $element.children(),
        oldId = $element.attr("id"),
        newId = (oldId) ? oldId.replace(/\d+$/, newIdNumber) : null;

    if (newId) {
        $element.attr("id", newId);
    }

    if ($elementChildren.length > 0) { // recursively call function on children
        $elementChildren.each(function(i, child) {
            changeIdNumberOnElementAndChildren(child, newIdNumber);
        });
    }
}

Then simply call it on a clone to change the ids:

$(function() {
    var clone = $("#wrapper1").clone();
    // below changes the ids so that they end in 559 rather than 1
    // (i.e. "wrapper559", "test559" and "my-awesome-id559")
    changeIdNumberOnElementAndChildren(clone, 559);
});

Upvotes: 0

j08691
j08691

Reputation: 207881

This would do it and create a clone like:

<div id="wrapper2">
  <p id="test2">Hello</p>
  <p id="my-awesome-id2"></p>
</div>

$('div').clone().filter(function() {
  $(this).prop('id', $(this).prop('id').replace('1', '2')).children().filter(function() {
    return $(this).prop('id', $(this).prop('id').replace('1', '2'))
  });
  return $(this)
}).appendTo('body')
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id='wrapper1'>
  <p id='test1'>Hello</p>
  <p id='my-awesome-id1'></p>
</div>

Upvotes: 3

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