CODEWITHSUNDEEP
cstring
Fdoh
Fdoh

Reputation: 1

C Splitting up a char string that contains an integer

I am trying to split up a string into 3 variables of type int,char,int. I have the following string to split 1000P3. I have the following code to do this but the char variable is containg the P3 instead of just the P. 

int num1;
char type [10];
int num2 =0;
sscanf("1000P3","%d %c %d",&num1,type,&num2);

Any assistance would be grateful.

Upvotes: 1

Views: 141

Answers (2)

ryyker
ryyker

Reputation: 23218

An array of char that is null terminated is a string, and its name happens to be a pointer to an address already. so you can just use:

char type[10];

you would use:

sscanf("1000P3","%d %s %d",&num1,type,&num2);
                     ^           ^

A single char is treated just as you would an int. To read its value, pass the address of the variable using the & operator.
So with 

char type;

you would use:

sscanf("1000P3","%d %c %d",&num1,&type,&num2);
                     ^           ^

Upvotes: 2

Antti Haapala -- Слава Україні
Antti Haapala -- Слава Україні

Reputation: 133919

%c reads a single character, not a character string. That you saw 3 was just a coincidence from undefined behaviour. Try

int num1;
char type;
int num2;
sscanf("1000P3","%d %c %d", &num1, &type, &num2);

And remember to printf the character also with %c.

Also you should check the return value of sscanf; if it is not 3 (as we wanted to parse 3 items), then your input is incorrect.

Upvotes: 2

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