CODEWITHSUNDEEP
python
Belvi Nosakhare
Belvi Nosakhare

Reputation: 3255

Check if string is contained in list element

I have a sample list of possible incident:

incident = [
    "road", "free", "block", "bumper", "accident","robbery","collapse","fire","police","flood"]

and i want to check if a sentence has any of this words in it.

eg. "the building is on fire"

this should return true since the list has fire in it and return false if otherwise.

I tried doing it with this method :

query = "@user1 @handler2 the building is on fire"

if any(query in s for s in incidentList):
    print("yes")
else:
    print("no")

but it always fail as oppose to when query = "fire".

Edit

and in situation when incident contains an element say: "street fight", i want it to return true assuming the query contains either street or fight. How do i fix this?

Upvotes: 0

Views: 124

Answers (3)

Sourav
Sourav

Reputation: 504

Hope this helps..

import sys
incident = ["road", "free", "block", "bumper", "accident","robbery","collapse","fire","police","flood", "street fight"]
sentence = "street is awesome"
sentence = sentence.split()
for word in sentence:       
    for element in incident:
        if word in element.split():
            print('True')
            sys.exit(0)

Upvotes: 1

alecxe
alecxe

Reputation: 473863

s refers to every incident in the list of incidents, check if s is in query instead:

if any(s in query for s in incidentList):

and in situation when incident contains an element say: "street fight", i want it to return true assuming the query contains either street or fight. How do i fix this?

Then, either improve the incidentList to contain individual words only, or you should also split the s in the loop:

if any(any(item in query for item in s.split()) for s in incidentList):

Upvotes: 6

Ian
Ian

Reputation: 30813

You are almost there, just need to do it the reverse way:

incident = [
    "road", "free", "block", "bumper", "accident","robbery","collapse","fire","police","flood"]

query = "@user1 @handler2 the building is on fire"

if any(s in query for s in incident):
    print("yes")
else:
    print("no")

Which makes sense, because you want to check for every s in incident (any word, including fire), if that s (that is, fire) is in query too.

You do not want to say if query (that is, your whole sentence) is in s (that is, a word like fire)

Upvotes: 3

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