CODEWITHSUNDEEP
sqlapache-spark-sql
shakedzy
shakedzy

Reputation: 2893

SQL on Spark: How do I get all values of DISTINCT?

So, assume I have the following table:

Name | Color
------------------------------
John | Blue
Greg | Red
John | Yellow
Greg | Red
Greg | Blue

I would like to get a table of the distinct colors for each name - how many and their values. Meaning, something like this:

Name | Distinct | Values
--------------------------------------
John |   2      | Blue, Yellow
Greg |   2      | Red, Blue

Any ideas how to do so?

Upvotes: 8

Views: 27774

Answers (2)

SummerEla
SummerEla

Reputation: 1952

For PySPark; I come from an R/Pandas background, so I'm actually finding Spark Dataframes a little easier to work with.

To do this:

  1. Setup a Spark SQL context
  2. Read your file into a dataframe
  3. Register your dataframe as a temp table
  4. Query it directly using SQL syntax
  5. Save results as objects, output to files..do your thing

Here's a class I created to do this: 

class SQLspark():

def __init__(self, local_dir='./', hdfs_dir='/users/', master='local', appname='spark_app', spark_mem=2):
    self.local_dir = local_dir
    self.hdfs_dir = hdfs_dir
    self.master = master
    self.appname = appname
    self.spark_mem = int(spark_mem)
    self.conf = (SparkConf()
           .setMaster(self.master)
           .setAppName(self.appname)
           .set("spark.executor.memory", self.spark_mem))
    self.sc = SparkContext(conf=self.conf)
    self.sqlContext = SQLContext(self.sc)


def file_to_df(self, input_file):
    # import file as dataframe, all cols will be imported as strings
    df = self.sqlContext.read.format("com.databricks.spark.csv").option("header", "true").option("delimiter", "\t").option("inferSchema", "true").load(input_file)
    # # cache df object to avoid rebuilding each time
    df.cache()
    # register as temp table for querying, use 'spark_df' as table name
    df.registerTempTable("spark_df")
    return df

# you also cast a spark dataframe as a pandas df
def sparkDf_to_pandasDf(self, input_df):
    pandas_df = input_df.toPandas()
    return pandas_df

def find_distinct(self, col_name):
    my_query = self.sqlContext.sql("""SELECT distinct {} FROM spark_df""".format(col_name))
   # now do your thing with the results etc
    my_query.show() 
    my_query.count()
    my_query.collect()

###############
if __name__ == '__main__':

# instantiate class 
# see function for variables to input
spark = TestETL(os.getcwd(), 'hdfs_loc', "local", "etl_test", 10)


# specify input file to process
tsv_infile = 'path/to/file'

Upvotes: 0

Zahiro Mor
Zahiro Mor

Reputation: 1718

collect_list will give you a list without removing duplicates. collect_set will automatically remove duplicates so just 

select 
Name,
count(distinct color) as Distinct, # not a very good name
collect_set(Color) as Values
from TblName
group by Name

this feature is implemented since spark 1.6.0 check it out:

https://github.com/apache/spark/blob/master/sql/core/src/main/scala/org/apache/spark/sql/functions.scala

/**
   * Aggregate function: returns a set of objects with duplicate elements eliminated.
   *
   * For now this is an alias for the collect_set Hive UDAF.
   *
   * @group agg_funcs
   * @since 1.6.0
   */
  def collect_set(columnName: String): Column = collect_set(Column(columnName))

Upvotes: 11

Related Questions