CODEWITHSUNDEEP
javaregex
Bobby
Bobby

Reputation: 496

regex match exclamation points java

I'm very new to regex and i'm struggling with a tiny project which can really help in my project. I want to know how to count groups of (consecutive)sequence of exclamation point. For instance lets consider the following string 

String s = "OMG!!!, i love Computers !!!! and this !!! is really good!"

the count here should return 3. I tried the following, but it's nothing like what i want public static int exclamation(String list) throws Exception{

String[] words = (list.split("\\s+"));
  Pattern pattern = Pattern.compile("\\*?(!!)*\\b");
int count = 0;
for(String s:words)
{       
    Matcher matcher = pattern.matcher(s);       
    if(pattern.matcher(s) != null)
    {
        System.out.println(s);

    }
}

return count;

}

Upvotes: 1

Views: 1784

Answers (1)

Avinash Raj
Avinash Raj

Reputation: 174796

Your regex won't print any ! mark because of \b. Your regex expects a word character to be present next to !, but in real there isn't a word character following ! but a non-word character space.

Pattern pattern = Pattern.compile("\\*?(!{2,})");

or

Pattern pattern = Pattern.compile("!{2,}");

DEMO

Upvotes: 2

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