Reputation: 6365
I have a file like this (this is sample):
71.13.55.12|212.152.22.12|71.13.55.12|8.8.8.8
81.23.45.12|212.152.22.12|71.13.55.13|8.8.8.8
61.53.54.62|212.152.22.12|71.13.55.14|8.8.8.8
21.23.51.22|212.152.22.12|71.13.54.12|8.8.8.8
...
I have iplist.txt like this:
71.13.55.
12.33.23.
8.8.
4.2.
...
I need to grep if 3. column starts like in iplist.txt.
Like this:
71.13.55.12|212.152.22.12|71.13.55.12|8.8.8.8
81.23.45.12|212.152.22.12|71.13.55.13|8.8.8.8
61.53.54.62|212.152.22.12|71.13.55.14|8.8.8.8
I tried:
for ip in $(cat iplist.txt); do
awk -v var="$ip" -F '|' '{if ($3 ~ /^$var/) print $0;}' text.txt
done
But bash variable does not work in /^ /
regex block. How can I do that?
Upvotes: 0
Views: 131
Reputation: 10865
First, you can use a concatenation of strings for the regular expression, it doesn't have to be a regex block. You can say:
'{if ($3 ~ "^" var) print $0;}'
Second, note above that you don't use a $
with variables inside awk. $
is only used to refer to fields by number (as in $3
, or $somevar
where somevar
has a field number as its value).
Third, you can do everything in awk in which case you can avoid the shell loop and don't need the var:
awk -F'|' 'NR==FNR {a["^" $0]; next} { for (i in a) if ($3 ~ i) {print;next} }' iplist.txt r.txt
71.13.55.12|212.152.22.12|71.13.55.12|8.8.8.8
81.23.45.12|212.152.22.12|71.13.55.13|8.8.8.8
61.53.54.62|212.152.22.12|71.13.55.14|8.8.8.8
EDIT
As rightly pointed out in the comments, the .
s in the patterns will match any character, not just a literal .
. Thus we need to escape them before doing the match:
awk -F'|' 'NR==FNR {gsub(/\./,"\\."); a["^" $0]; next} { for (i in a) if ($3 ~ i) print }' iplist.txt r.txt
I'm assuming that you only want to output a given line once, even if it matches multiple patterns from iplist.txt. If you want to output a line multiple times for multiple matches (as your version would have done), remove the next
from {print;next}
.
Upvotes: 3
Reputation:
Here is a way with bash
, sed
and grep
, it's straight forward and I think may be a bit cleaner than awk
in this case:
IFS=$(echo -en "\n\b") && for ip in $(sed 's/\./\\&/g' iplist.txt); do
grep "^[^|]*|[^|]*|${ip}" r.txt
done
Upvotes: 1
Reputation: 4887
Use var
directly, instead of in /^$var/
( adding ^
to the variable first):
awk -v var="^$ip" -F '|' '$3 ~ var' text.txt
By the way, the default action for a true condition is to print the current record, so, {if (test) {print $0}}
can often be contracted to just test
.
Upvotes: 2