Reputation: 33
I'm using boost 1.54.0 and Visual Studio 2010. For the code:
#include <iostream>
#include "boost/thread/thread.hpp"
#include "boost/thread/mutex.hpp"
boost::mutex mx1;
void func1()
{
{
boost::mutex::scoped_lock(mx1);
std::cout << "Thread " << boost::this_thread::get_id() << " starting work." << std::endl;
}
int x = 0;
for (int i=0; i<100; i++)
x++;
{
boost::mutex::scoped_lock(mx1);
std::cout << "Thread " << boost::this_thread::get_id() << " finished." << std::endl;
}
}
int main(void)
{
boost::thread thread1(&func1);
boost::thread thread2(&func1);
thread1.join();
thread2.join();
return 0;
}
About half the time I get the following (with varying thread ids and execution order, obviously):
Thread Thread 15b0 starting work.
1a18 starting work.
Thread 15b0 finished.
Thread 1a18 finished.
...instead of this (which is what I'd expect):
Thread 15b0 starting work.
Thread 1a18 starting work.
Thread 15b0 finished.
Thread 1a18 finished.
However, using
mx1.lock();
std::cout << "Thread " << boost::this_thread::get_id() << " starting work." << std::endl;
mx1.unlock();
...seems to work with no problems.
The output always seems to follow the same pattern. Am I using the mutex incorrectly, or is it something to do with std::cout?
Upvotes: 1
Views: 155
Reputation: 18864
Replace
boost::mutex::scoped_lock(mx1);
with
boost::mutex::scoped_lock lock(mx1);
you fell a victim of the most frequently occurring typo with the scoped lock:-)
Upvotes: 6