CODEWITHSUNDEEP
javastringprintln
Blackbox10101
Blackbox10101

Reputation: 13

choose a position on printed wire, java string

I am attempting to have my program print(command window) this> "----------" in any length from 1 - 100:

public void display()
   {
       for (int x=0; x < Length; x++)
       {
           System.out.print("-");
       }
   }

However, I need a "bug" to land somewhere on this wire: for example: ----0---- and be able to remember that position and move along the wire. I am not asking for the answer to solve this but help on what keywords to lookup and reading on something like this.

Thanks for the help!

Upvotes: 0

Views: 115

Answers (2)

ninja.coder
ninja.coder

Reputation: 9658

However, I need a "bug" to land somewhere on this wire

You can use Random as follows:

public static void main (String[] args) throws Exception
{
    Random rnd = new Random();
    int randomNumber = rnd.nextInt(100);

    char[] chr = new char[100];
    Arrays.fill(chr,'-');
    chr[randomNumber] = '0';

    System.out.print(new String(chr));
}

Here, randomNumber will hold the position of the bug for you.

Upvotes: 1

L. Kolar
L. Kolar

Reputation: 555

One way of doing that is by calling method with argument that specifies position of the bug. That way you know position of the bug.

public void display(int position)
   {
       for (int x=0; x < Length; x++)
       {
            if (x == position) {
                System.out.print("O");
            }
            else {
                System.out.print("-");
            }
       }
   }

Upvotes: 1

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