CODEWITHSUNDEEP
arraysruby
anonn023432
anonn023432

Reputation: 3120

Break text file into separate words and store in array in Ruby

I'm trying to read a text file and then store its individual words in an array. But I can't find a way to split it according to words.

text_file = []

File.open(file, "r") do |f|
  f.lines.each do |line|
    text_file << line.split.map(&:to_s)
  end
end

The above method creates an array of arrays which stores all the words in a single line in an array and so on.

Is there a way in which the array text_file can hold a single array of all the words?

Upvotes: 0

Views: 1617

Answers (4)

Mike Slinn
Mike Slinn

Reputation: 8403

The following reads the contents of file, splits lines and words delimited by spaces, and then makes a constant called WORDS by freezing the result.

WORDS = File.read(file).split(/[ \n]/).freeze

If you also want to use tabs as well as spaces and newlines as delimiters use the following:

WORDS = File.read(file).split(/[ \n\t]/).freeze

Upvotes: 0

Sagar Pandya
Sagar Pandya

Reputation: 9497

Modifying your code, this will do the trick:

text_file = []

File.open('document.rb', "r") do |f|
  f.each_line do |line|
    arr = line.split(' ')
    arr.each do |word|
      text_file << word
    end  
  end
end

Upvotes: 0

tadman
tadman

Reputation: 211590

If you want all of the words, uniquely, sorted:

text_file = [ ]

File.open(file, "r") do |f|
  f.each_line do |line|
    text_file += line.split
  end
end

text_file.uniq!
text_file.sort!

This is not the most optimal implementation, but it should work. To adapt this to more real-world situations you probably need to use String#scan to pull out more specific words instead of getting tripped up on things like punctuation or hyphens.

Upvotes: 1

sawa
sawa

Reputation: 168101

Yes. Either do:

text_file.push(*line.split.map(&:to_s))

or:

text_file.concat(line.split.map(&:to_s))

Upvotes: 2

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