CODEWITHSUNDEEP
pythonhtml-parsing
Stev0
Stev0

Reputation: 605

Python 2.7, ValueError when dealing with HTMLParser

First time working with the HTMLParser module. Trying to use standard string formatting on the ouput, but it's giving me an error. The following code:

import urllib2
from HTMLParser import HTMLParser

class LinksParser(HTMLParser):
    def __init__(self, url):
        HTMLParser.__init__(self)
        req = urllib2.urlopen(url)
        self.feed(req.read())

    def handle_starttag(self, tag, attrs):
        if tag != 'a': return
        for name, value in attrs:
        print("Found Link --> {]".format(value))


if __name__ == "__main__":
    LinksParser("http://www.facebook.com"

Produces the following error: 

File "C:\Users\workspace\test\src\test.py", line 15, in handle_starttag  
print("Found Link --> {]".format(value))  
ValueError: unmatched '{' in format

Upvotes: 0

Views: 993

Answers (3)

Coding District
Coding District

Reputation: 11929

print("Found Link --> {]".format(value))

Should instead be:

print("Found Link --> {}".format(value))

You used a square bracket instead of a brace.

Upvotes: 2

Andre Holzner
Andre Holzner

Reputation: 18695

There are several problems

  • the print statement in handle_starttag should be indented
  • in the last line you're missing the closing parenthesis
  • in the print statement in handle_starttag you should use {0} instead of {]

Upvotes: 0

Manoj Govindan
Manoj Govindan

Reputation: 74795

This format string looks broken: print("Found Link --> {]".format(value)). You need to change this to print("Found Link --> {key}".format(key = value)).

Upvotes: 0

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