CODEWITHSUNDEEP
phpdate
Testadmin
Testadmin

Reputation: 2898

How convert a date from dd-mm-yy to mm-dd-yy

How convert a date from dd-mm-yy to mm-dd-yy

below is my code

<?
$date= date('d-m-y');
echo date('m-d-Y',strtotime($date));
?>

but the result is : 09-10-2001

i need 09-01-2010

Upvotes: 6

Views: 6301

Answers (5)

BMBM
BMBM

Reputation: 16013

You could use the sscanf function if you dont have PHP 5.3 available and make use of the argument swapping option:

$theDate = '01-02-03';
print join(sscanf($theDate, '%2$2s-%1$2s-%3$2s'), '-');
# output: 02-01-03

sscanf basically parses the provided string in an array based on the provided format, swapping the first matched argument (the day) with the second (the month), leaving the third one (year) untouched and then this array is joined again with the - as separator.

Upvotes: 0

jasonbar
jasonbar

Reputation: 13461

This won't work:

date('m-d-y', strtotime($the_original_date));

If you have PHP 5.3, you can do:

$date = DateTime::createFromFormat('d-m-y', '09-10-01');
$new_date = $date->format('m-d-Y');

Otherwise:

$parts = explode('-', $original_date);
$new_date = $parts[1] . '-' . $parts[0] . '-' . $parts[2];

Upvotes: 8

enricog
enricog

Reputation: 4273

If the format is always like above, this should work:

$pieces = explode("-", $yourTimestring);
$timestamp = mktime(0,0,0,$pieces[1], $pieces[0], $pieces[2]);
$newDateStr = date("m-d-y", $timestamp);

Edit: True, just saw the answer from "codaddict" and yeah, if i alredy split it up you could also concatenate it directly ^^

Upvotes: 0

codaddict
codaddict

Reputation: 454960

You can do:

$input = 'dd-mm-yy';
$a = explode('-',$input);
$result = $a[1].'-'.$a[0].'-'.$a[2];

Upvotes: 3

pymendoza
pymendoza

Reputation: 358

try this date("m-d-y", {your date variable})

Upvotes: 0

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