CODEWITHSUNDEEP
c++winapivisual-c++
rel1x
rel1x

Reputation: 2441

Convert LOWORD(wParam) to const wchar_t*

I develop calculator app as a homework and and I check which digit is pressed like this: 

if (LOWORD(wParam) == buttonDigit0) {
    writeToOperand(L"0");
}
else if (LOWORD(wParam) == buttonDigit1) {
    writeToOperand(L"1");
}
else if (LOWORD(wParam) == buttonDigit2) {
    writeToOperand(L"2");
}
// ...

Where writeToOperand is void writeToOperand(const wchar_t* digit);

And I want to minify it like this:

if (LOWORD(wParam) >= 100 && LOWORD(wParam) <= 109) {
   writeToOperand(LOWORD(wParam));
}

Where 100 is id of button #define buttonDigit0 100 and 109 is #define buttonDigit9 109. But I don't follow how can I convert LOWORD(wParam) to const wchar_t* for my writeToOperand function.

Upvotes: 0

Views: 485

Answers (1)

Serge Ballesta
Serge Ballesta

Reputation: 149075

You just have to use a local wchar_t array variable to store the computed digit:

wchar_t digit[2] = {0}; // reserve place for terminating null...
if (LOWORD(wParam) >= 100 && LOWORD(wParam) <= 109) {
   digit[0] = static_cast<wchar_t>('0' + LOWORD(wParam) - 100); // explicit cast to avoid a warning
   writeToOperand(digit);
}

But you must compute the actual value and store it into a local array to be able to pass the address to writeToOperand

Upvotes: 2

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