CODEWITHSUNDEEP
pythondjangodjango-viewsdjango-templates
Hulk
Hulk

Reputation: 34180

Decode values of a tuple in django template

  if(len(f1) > 0):  
    for qs in profile_map:
        p = Profile.objects.get(pk=qs.emp.id)
        t_name = p.first_name + p.last_name
        t_arr.append((q.profile.id,emp_name))
    response_dictionary.update({'tarr':t_arr})
  render_to_response('project/profile_table.html',context_instance=RequestContext(request,{'response_dictionary': response_dictionary}))

In Django template How to deocode all the 1.values of the tuple 2.search the tuple for a certain value in q.profile.id

        {% for ele in response_dictionary.tarr%}
            alert('{{ele}}');
        //Get this as alert (11L, u'Employee3.')
         {% endfor %}

Upvotes: 1

Views: 3534

Answers (2)

Filip Dupanović
Filip Dupanović

Reputation: 33680

In your case, the generator will assign the tuple to ele, so you can access the first, last name with {{ ele.0 }} {{ ele.1 }}.

But this is also legal, to unpack the tuple into two vars:

{% for first_name, last_name in response_dictionary.tarr %}

Upvotes: 3

Bojan Babic
Bojan Babic

Reputation: 603

if you are using django 0.96 you can't have multiple values in for loop. so this will not work:

{% for first_name, last_name in response_dictionary.tarr %}

instead use 

{% for ele in response_dictionary.tarr %}
     {{ ele.0 }} {{ ele.1 }}
{% endfor %}

Upvotes: 3

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