CODEWITHSUNDEEP
shellprintf
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Reputation: 30

What does mean the parameter %0.2f% with two percents symbols in printf

I'm working with one file.sh, but I didn't understood what does two percent symbols means %0.2f%.

The command read a value in tmp.err and print it, just this, look below:

awk '{ printf("*** Error: %0.2f%\n",substr($2, 2, length($2) - 2) * 100) }' tmp.err

The file tmp.err have this two values separated by white space 11736 (0.17908).

I already know %0.2f means a float value with two decimals.

someone know what does %0.2f% do? or is a typo?

I'm asking this question, because right now I'm receiving an error, not enough arguments passed to printf( bu if I remove the last percentage like this %0.2f works fine.

thanks

Upvotes: 0

Views: 2440

Answers (1)

chepner
chepner

Reputation: 531075

The fact that the argument is multiplied by 100 leads me to think that whoever wrote that intended for a literal percent sign, which needs to be doubled.

awk '{ printf("*** Error: %0.2f%%\n",substr($2, 2, length($2) - 2) * 100) }' tmp.err

Upvotes: 2

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