CODEWITHSUNDEEP
ruby
user6105070
user6105070

Reputation:

undefined method `split' for #<Enumerator:0x007fcb41399a90> Ruby

Ive bee set the following task and keep getting the error mentioned in the title but cant figure out why. Any help would be great.

# Given a sentence, return an array containing every other word.
# Punctuation is not part of the word unless it is a contraction.
# In order to not have to write an actual language parser, there won't be any punctuation too complex.
# There will be no "'" that is not part of a contraction.
# Assume each of these  charactsrs are not to be considered: ! @ $ # % ^ & * ( ) - = _ + [ ] : ; , . / < > ? \ |
#
# Examples
# alternate_words("Lorem ipsum dolor sit amet.")  # => ["Lorem", "dolor", "amet"]
# alternate_words("Can't we all get along?")      # => ["Can't", "all", "along"]
# alternate_words("Elementary, my dear Watson!")  # => ["Elementary", "dear"]

def alternate_words(string)

   no_p = string.gsub(/[^a-z ^A-Z ^0-9 ']/)
   new_words = []

   no_p.split.each.with_index {|x,i| new_words << string[i] if i.even? }

   new_words
end

Upvotes: 0

Views: 332

Answers (2)

Jonah
Jonah

Reputation: 17958

String.gsub returns an Enumerator when passed only a single argument. You need to specify a replacement or block for that method to return a String. split is a method on String, not on Enumerator, hence your error.

Upvotes: 0

archana
archana

Reputation: 1272

no_p = string.gsub(/[^a-z ^A-Z ^0-9 ']/) you are not using gsub correctly. What are the replacement chars? See http://ruby-doc.org/core-2.1.4/String.html#method-i-gsub. If you do not provide a replacement then gsub returns an Enumerator object.

Upvotes: 1

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