CODEWITHSUNDEEP
scalatypes
user3439308
user3439308

Reputation: 495

Scala String and Char Types

val args = "To now was far back saw the *$# giant planet itself, het a won"

Find and sort distinct anagram pairs from "args": 

now won

was saw 

the het

First I clean up the args and put them in an array.

val argsArray = args.replaceAll("[^a-zA-Z0-9\\s]", "").toLowerCase.split(" ").distinct.sorted 
argsArray: Array[String] = Array("", a, back, far, giant, het, itself, now, planet, saw, the, to, was, won)

My idea is to reduce each word to an array of char, then sort, then compare. But I get stuck because the following returns the wrong data type ---- String = [C@2736f24a

for (i <- 0 until argsArray.length - 1){
    val j = i + 1
    if(argsArray(i).toCharArray.sorted == argsArray(j).toCharArray.sorted) {
      println(argsArray(i).toCharArray + " " + argsArray(j).toCharArray)
    }
}

I assume there are better ways to solve this, but what I really want to learn is how to deal with this data type problem, so please help me solve that and then I will refactor later. Thank you.

Upvotes: 0

Views: 1276

Answers (1)

Alexey Romanov
Alexey Romanov

Reputation: 170713

[C@<whatever> is just how Array[Char] is converted to String on JVM. Remove calls to toCharArray from println and it'll print the strings you want. The second error, with the current code in the question, is the equality check: == on arrays checks that they are the same object, and since sorted will always create a new array, the left and right sides are always different objects even if they have the same elements.

Upvotes: 1

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