CODEWITHSUNDEEP
assemblyx86-16emu8086
Tawabul_Islam_Piash
Tawabul_Islam_Piash

Reputation: 11

How to declare and manipulate an array of Strings in 8086 assembly language?

I am working in emu8086 version 4.08. I have to make a student database. So, if I want to store a list of names or ID in an array of strings how can I do it? or is there any other way? Thanks in advance.

Here is the code I am trying: 

include 'emu8086.inc' 

.model small
.stack 100h  


.data  


  str2 dw 20 dup('$')

.code   

  mov ax,@data
  mov ds,ax

main proc



  mov si,0





  mov str2[si],"student1$"
  add si,1  

  mov str2[si],"student2$"
  add si,1

  mov str2[si],"student3$"
  add si,1

  mov str2[si],"student4$"



mov ah,4ch 
int 21h               

endp main 


DEFINE_SCAN_NUM
DEFINE_PRINT_STRING
DEFINE_PRINT_NUM
DEFINE_PRINT_NUM_UNS  
DEFINE_PTHIS

Upvotes: 0

Views: 8504

Answers (1)

Sep Roland
Sep Roland

Reputation: 39166

mov str2[si],"student1$"

You're wrong in what SI stands for. You think that it is an index in the array, but is is not. In assembly language it is an offset in memory (measured in bytes).

The string "student1$" has 9 characters and so you must provide room to store all of those characters, 1 byte per character. Furthermore you can't assign the complete string in one go. You'll have to use a loop for that.

First change the definition of the array and store the name in a tempory location:

str2 db 4*10 dup(0)
sname db "student1$"

This will give room for storing 4 student names of 9 characters plus an extra terminating character (if wanted).

Next use a loop to write a student name:

 mov di, offset str2
 mov si, offset sname
More:
 mov al, [si]
 mov [di], al
 inc si
 inc di
 cmp al, "$"
 jne More

For the next student the name will have to be written to str2 + 10

Upvotes: 3

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