CODEWITHSUNDEEP
hibernatecriteriaquery-by-example
Nox
Nox

Reputation: 181

Hibernate Criteria by Examle

I am trying to create Criteria by an Example. But I am getting the same results for the different Example objects.

Author author = new Author();
author.setId(3L);
News news = new News();
news.setAuthor(author);

List<News> newsList = getSession().createCriteria(News.class)
           .add(Example.create(news))
           .list();

If I change the id, then I get the the same news list. I tried to do next:

//...
.add(Example.create(news.getAuthor())

But it doesn't work too. I know that I can use for example Restrictions or HQL, but I would like to try do it like that. How to use the Examle correctly?

Upvotes: 0

Views: 71

Answers (1)

JB Nizet
JB Nizet

Reputation: 691635

From the documentation

Version properties, identifiers and associations are ignored. By default, null valued properties are excluded.

Upvotes: 1

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