CODEWITHSUNDEEP
javascriptmathfinancial
Student2792
Student2792

Reputation: 77

Financial calculation with JavaScript (What´s wrong?)

I'm trying to make a financial calculation, but there's something wrong.

JS Code:

function count (){

var coda = 1.500;
var codb = 15;
var codc = 0.06;
var codx = 1;

var result = (codc/codx(codx-((codx+codc)*-codb)))*coda;

alert(result);


}

Message: undefined

Upvotes: 0

Views: 284

Answers (7)

Lutz Lehmann
Lutz Lehmann

Reputation: 25972

If this relates to paying down a loan at interest i per payment period, then you get that after n payments at a rate of r the reduced principal is

p*(1+i)^n-r*(1+i)^n-r*(1+i)^(n-1)-...-r*(1+i) 
=
p*(1+i)^n - (1+i)*((1+i)^n-1)/i*r

If that is to be zero, loan repaid, then the necessary rate computes as 

r = i/((1+i)*(1-(1+i)^(-n))) * p

which is in some aspects similar, in other fundamental aspects different from your formula.

var p = 1.500;
var n = 15;
var i = 0.06;
var x = 1+i;

var result = i/( x*( 1-Math.pow(x,-n) ) )*p;

alert(result);

Upvotes: 0

Shaker
Shaker

Reputation: 33

var count = function () {
 var coda = 1.5; var codb = 15; var codc = 0.06; var codx = 1;
 var result = (codc/codx ** here ** (codx-((codx+codc)* - codb))) *  coda;    
 console.log(result);
}

P.S you have to put something after codx it's seen by javascript as an undefined function.

Upvotes: 0

Ronak Patel
Ronak Patel

Reputation: 3444

In this case,

It is better to split the mathematical calculation.

Example:

function count (){

var coda = 1.500;
var codb = 15;
var codc = 0.06;
var codx = 1;

var res1 = ((codx+codc)*-codb);
var res2 = codx-res1;
var result = (codc/codx*res2)*coda;

alert(result);

}

Upvotes: 0

teroi
teroi

Reputation: 1087

Slightly off-topic but you should never use floating point arithmetic in financial calculations. Instead calculate by integer cents and then format for viewing as you like.

Upvotes: 0

Pimmol
Pimmol

Reputation: 1871

In this line var result = (codc/codx(codx-((codx+codc)*-codb)))*coda;

You try to execute the 2nd codx as a function (codx()). I guess you miss an operand there.

Try for example: var result = (codc/codx / (codx-((codx+codc)*-codb)))*coda;

Upvotes: 1

Paul Humphreys
Paul Humphreys

Reputation: 338

Missing * symbol? codx is being used as a fuction as a result.

var coda = 1.500;
var codb = 15;
var codc = 0.06;
var codx = 1;

var result = (codc/codx*(codx-((codx+codc)*-codb)))*coda;

alert(result);

Upvotes: 0

cl3m
cl3m

Reputation: 2801

You are missing a * operator, so the compiler tries to call codx as a function.

To fix your computation, add the * operator as follow:

function count (){

    var coda = 1.500;
    var codb = 15;
    var codc = 0.06;
    var codx = 1;

    var result = (codc/codx * (codx - ((codx+codc)*-codb)))*coda;
    //                      ^

    alert(result);
}

Upvotes: 0

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