Reputation: 65
I have a list of 40 data sets who all have the same columns. I want to bind the 7th column of each data set. I thought about doing this with a matrix using cbind. This is my code:
RetRates <- function(q) {
q <- matrix(nrow = 766, ncol = length(ListeActions),
data = rep(0, 766), byrow = TRUE)
s <- 0
for (i in 1:length(ListeActions)) {
x <- ListeActions[[i]]
q[,i] <- cbind(q[,i], x[,9]) ## I need the 9th column
}
return(q)
}
Hedi <- matrix(nrow = 766, ncol = length(ListeActions),
data = rep(0, 766), byrow = TRUE)
Hedi <- RetRates(Hedi)
I get these warnings :
Warning messages: 1: In replace(q[, i], 1:766, x[, 9]) : the number of objects to be replaced is not a multiple of the size of the replacement !
Upvotes: 0
Views: 164
Reputation: 3429
Let's take a smaller example: cbind
the 5th columns of each of these 3 matrices
d1 <- matrix(runif(30), 5, 6)
d2 <- matrix(rnorm(30), 5, 6)
d3 <- matrix(rnorm(30), 5, 6)
First we put the 3 matrices in a list
M <- list(d1=d1, d2=d2, d3=d3)
Then we could use, as in your question, a for
loop
res1 <- matrix(NA, nrow=5, ncol=length(M))
for (i in 1:length(M)) {
res1[, i] <- M[[i]][,5]
}
Or we could use some magical R functions to get the result in one slightly more obscure command
res2 <- do.call(cbind, lapply(M, "[",,5))
Upvotes: 1