Making two branches identical

Question

I have two branches - A and B. B was created from A.

Work on both branches continued in parallel. Work on branch A was bad (resulting in a non-working version) while work on branch B was good. During this time branch B was sometimes merged into branch A (but not the other way around).

Now I want to make branch A identical to branch B. I can't use git revert because I need to revert too many commits - I only want to revert the commits that were done on branch A but not as a result of merging branch B.

The solution I found was to clone branch B into a another folder, delete all the files from the working folder of branch A, copy the files from the temp branch B folder and add all untracked files.

Is there a git command that does the same thing? Some git revert switch I missed?

Answer 1

I was struggling with this because I didn't realize a soft reset also immediately and permanently altered local branch state—creating a branch if it doesn't already exist! So when I checked out a tag and did a soft reset, I created a branch by that name with HEAD at the reset target. Oops!

This is the process I use to update one branch's state to another's (or in my case, to a release tag) using a single commit:

1. git checkout <tag-to-mirror> - can be anything; branch, tag, commit
2. git checkout -b DELETE_ME - give git something to screw up
3. git reset --soft <branch-to-update> - create a changeset that makes <branch-to-update> look like <tag-to-mirror> (currently in the DELETE_ME branch)
4. git checkout <branch-to-update> - actually apply your current changeset to that branch, and establish where commits will go.
5. git commit -m "Fast-forward to <tag-to-mirror>" - commit the change.
6. git branch -D DELETE_ME; git diff <tag-to-mirror> - clean up, prove to yourself you've succeeded.

If you skipped step 2 as I did and are wondering how you can infinitely apply the same changeset to your branch and never get the two branches to look alike, you can just delete the <tag-to-mirror> branch and re-create it from origin/<tag-to-mirror> or whatever the original commit was.

So, if you just wanted to make master look like devel, for example, you could run this:

git checkout devel
git checkout -b DELETE_ME
git reset --soft master
git checkout master
git commit -m "Fast-forward master to devel"
git branch -D DELETE_ME  # Clean up.
git diff devel  # Should show no changes.

YMMV if you attempt to do a normal merge after that, as none of the commits from devel will appear in the history of master this way. You'd be amazed at Git's ability to generate merge conflicts for files that, in fact, are identical in both branches at the time of merge. I personally only needed to do this because we have local repositories for the versions of certain third-party libraries we use, and I just want to silently roll up from one version to another.

Answer 2

All other answers seemed either a bit complex or did not have quite the correct syntax for me. To make A the same as the current B:

  git checkout A
  git reset origin/B --hard
  git push --force

Answer 3

here is the nice way I am using to do this for me. The idea is to get diff of A and B, commit that diff, revert that to create opposite commit and than cherry-pick that last revert commit to A

here are the commands

git checkout B
git checkout -b B_tmp 
git merge --squash A
git commit -a -m 'A-B diff'
git revert B_tmp
git checkout A                    
git cherry-pick B_tmp
git branch -d B_tmp

and here you are, A is the same as B, and you have only one commit in A history that resets to be the same as B branch.

Check the bash script, you chave to change your repo directory and branch names, those are not variable yet, but can be easily managed
https://github.com/serg94/git_bash/blob/master/reset_dev

Answer 4

Checkout your target branch:

git checkout A;

To remove everything in branch A and make it to be the same as B:

git reset B --hard;

If you need to discard all your local changes (kind of revert, but doesn't mess up git like git revert):

git reset HEAD --hard;

When you are done, don't forget to update your remote branch (use --force or -f flag in case you need to override history).

git push origin A -f;

Answer 5

 git merge A 

is the best way to make 2 branches identical if the head is in branch b

Answer 6

The answers in this post are way too complicated for my taste.

Here's what I did:

Assuming you're on the branch you want to change

Step 1 - Make the branch the same as master

git reset origin/master --hard

Step 2 - Pull the branch that you want to be identical to

git pull origin branch-i-want-to-be-identical-to

Step 3 (optional) - Force push it to remote to overwrite the remote history

git push --force

Answer 7

Here is a last resort idea (it's dirty and not a git way of doing things)...

1. Go to branch B (git checkout B).
2. Copy all the content of that branch(ctrl + c)
3. Go to branch A (git checkout A)
4. Delete everything from branch A (select all with mouse and delete)
5. Copy all the content from the branch B in the folder where all the branch A stuff was. (ctrl + v)
6. Stage all the new changes (git add .)
7. Commit the staged changes (git commit -m "Branch A is now the same as B")

Answer 8

There are a lot of ways to do this and which one you should use depends on what result you want, and particular what you and anyone collaborating with you (if this is a shared repository) expect to see in the future.

The three main ways to do this:

1. Don't bother. Abandon branch A, make a new A2, and use that.

2. Use git reset or equivalent to re-point A elsewhere.

   Methods 1 and 2 are effectively the same in the long run. For instance, suppose you start by abandoning A. Everyone develops on A2 instead for a while. Then, once everyone is using A2, you delete the name A entirely. Now that A is gone, you can even rename A2 to A (everyone else using it will have to do the same rename, of course). At this point, what, if anything, looks different between the case where you used method 1 and the case where you used method 2? (There is one place you may still be able to see a difference, depending on how long your "long run" is and when you expire old reflogs.)

3. Make a merge, using a special strategy (see "alternative merge strategies" below). What you want here is -s theirs, but it doesn't exist and you must fake it.

Side note: where a branch is "created from" is basically irrelevant: git doesn't keep track of such things and in general it is not possible to discover it later, so it probably should not matter to you either. (If it really does matter to you, you can impose a few restrictions on how you manipulate the branch, or mark its "start point" with a tag, so that you can recover this information mechanically later. But this is often a sign that you are doing something wrong in the first place—or at the least, expecting something of git that git does not provide. See also footnote 1 below.)

Definition of branch (see also What exactly do we mean by branch?)

A branch—or more precisely, a branch name—in git is simply a pointer to some specific commit within the commit graph. This is also true of other references like tag names. What makes a branch special, as compared with a tag for instance, is that when you are on a branch and make a new commit, git automatically updates the branch name so that it now points to the new commit.

For instance, suppose we have a commit graph that looks something like this, where o nodes (and the one marked * as well) represent commits and A and B are branch-names:

o <- * <- o <- o <- o <- o   <-- A
      \
       o <- o <- o           <-- B

A and B each point to the tip-most commit of a branch, or more precisely, the branch data structure formed by starting at some commit and working back through all reachable commits, with each commit pointing to some parent commit(s).

If you use git checkout B so that you're on branch B, and make a new commit, the new commit is set up with the previous tip of B as its (single) parent, and git changes the ID stored under the branch name B so that B points to the new tip-most commit:

o <- * <- o <- o <- o <- o   <-- A
      \
       o <- o <- o <- o      <-- B

The commit marked * is the merge base of the two branch tips. This commit, and all earlier commits, is on both branches.¹ The merge base matters for, well, merging (duh :-) ), but also for things like git cherry and other release-management type operations.

You mention that branch B was occasionally merged back into A:

git checkout A; git merge B

This makes a new merge commit, which is a commit with two² parents. The first parent is the previous tip of the current branch, i.e., the previous tip of A, and the second parent is the named commit, i.e., the tip-most commit of branch B. Redrawing the above a bit more compactly (but adding some more -s to make the os line up better), we start with:

o--*--o--o--o--o      <-- A
    \
     o---o--o---o     <-- B

and end up with:

o--*--o--o--o--o--o   <-- A
    \            /
     o---o--o---*     <-- B

We move the * to the new the merge-base of A and B (which is in fact the tip of B). Presumably we then add some more commits to B and maybe merge a few more times:

...---o--...--o--o    <-- A
     /       /
...-o--...--*--o--o   <-- B

What git does by default with git merge <thing>

To make a merge, you check out some branch (A in these cases) and then run git merge and give it at least one argument, typically another branch name like B. The merge command starts by turning the name into a commit ID. A branch name turns into the ID of the tip-most commit on the branch.

Next, git merge finds the merge base. These are the commits we have been marking with * all along. The technical definition of the merge base is the Lowest Common Ancestor in the commit graph (and in some cases there may be more than one) but we'll just go with "the commit marked *" here for simplicity.

Last, for ordinary merges, git runs two git diff commands.³ The first git diff compares commit * against the HEAD commit, i.e., the tip of the current branch. The second diff compares commit * against the argument commit, i.e., the tip of the other branch (you can name a specific commit and it need not be the tip of a branch, but in our case we're merging B into A so we get those two branch-tip commits).

When git finds some file modified, as compared to the merge-base version, in both branches, git tries to combine those changes in a semi-smart (but not really smart) way: if both changes add the same text to the same region, git keeps one copy of the addition. If both changes delete the same text in the same region, git deletes that text just once. If both changes modify text in the same region, you get a conflict, unless the modifications match exactly (then you get one copy of the modifications). If one side makes one change and the other side makes a different change, but the changes seem not to overlap, git takes both changes. This is the essence of a three-way merge.

Last, assuming all goes well, git makes a new commit that has two (or more as we already noted in footnote 2) parents. The work-tree associated with this new commit is the one git came up with when it did its three-way merge.

Alternative merge strategies

While git merge's default recursive strategy has -X options ours and theirs, they do not do what we want here. These simply say that in the case of a conflict, git should automatically resolve that conflict by choosing "our change" (-X ours) or "their change" (-X theirs).

The merge command has another strategy entirely, -s ours: this one says that instead of diffing the merge base against the two commits, just use our source tree. In other words, if we're on branch A and we run git merge -s ours B, git will make a new merge commit with the second parent being the tip of branch B, but the source tree matching the version in the previous tip of branch A. That is, the code for the new commit will exactly match the code for its parent.

As outlined in this other answer, there are a number of ways to force git to effectively implement -s theirs. I think the simplest to explain is this sequence:

git checkout A
git merge --no-commit -s ours B
git rm -rf .         # make sure you are at the top level!
git checkout B -- .
git commit

The first step is to ensure that we are on branch A, as usual. The second is to fire up a merge, but avoid committing the result yet (--no-commit). To make the merge easier for git—this is not needed, it just makes things faster and quieter—we use -s ours so that git can skip the diff steps entirely and we avoid all merge conflict complaints.

At this point we get to the meat of the trick. First we remove the entire merge result, since it is actually worthless: we do not want the work-tree from the tip commit of A, but rather the one from the tip of B. Then we check out every file from the tip of B, making it ready to commit.

Last, we commit the new merge, which has as its first parent the old tip of A and as its second parent the tip of B, but has the tree from commit B.

If the graph just before the commit was:

...---o--...--o--o    <-- A
     /       /
...-o--...--*--o--o   <-- B

then the new graph is now:

...---o--...--o--o--o   <-- A
     /       /     /
...-o--...--o--o--*     <-- B

The new merge-base is the tip of B as usual, and from the perspective of the commit graph, this merge looks exactly like any other merge. What's unusual is that the source tree for the new merge at the tip of A exactly matches the source tree for the tip of B.

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¹In this particular case, since the two branches have remained independent (never been merged), it's also probably the point where one of the two branches was created (or maybe even where both were created), although you can't prove that at this point (because someone may have used git reset or various other tricks to move the branch labels around in the past). As soon as we start merging, though, the merge base is clearly no longer the starting point, and a sensible starting point gets more difficult to locate.

²Technically, a merge commit is any commit with two or more parents. Git calls merges with more than two parents "octopus merges". In my experience, they are not common except in the git repository for git itself, and in the end, they achieve the same thing as multiple ordinary two-parent merges.

³The diffs are usually done internally to some extent, rather than running actual commands. This allows a lot of short-cut optimizations. It also means that if you write a custom merge driver, that custom merge driver is not run unless git finds that the file is modified in both diffs. If it's only modified in one of the two diffs, the default merge simply takes the modified one.

Answer 9

You need to git reset branch A to branch B. See docs.