CODEWITHSUNDEEP
djangodjango-modelsdjango-templatesdjango-views
Charles Smith
Charles Smith

Reputation: 3289

Dynamically Create Django URL Slug in Function Based View

I have been banging my head against the wall for hours on this and its probably incredibly simple.

I need to generate two url slugs from one model. One is actually called slug and is a SlugField which is for the Product title, and the other is a category which is a ForeignKey.

Ideally what I would like to have is

url(r'^products/(?P<category>[^\.]+)/(?P<slug>[^\.]+)/$', tool_detail, name='tool_detail'),

But, the category part of the URL keeps giving generating an "invalid literal for int(), with base 10: 'category' - well, this is one of the errors, I tried many different combinations.

Model

...
slug = models.SlugField()
category = models.ForeignKey(Category)
...

View

def tool_detail(request, slug):
    tool = get_object_or_404(Tool, slug=slug)
    part = get_object_or_404(Part)
    return render(request, 'tool_detail.html', {'tool': tool, 'part': part})

Template

<a href="{% url 'tool_detail' t.category slug=t.slug %}" ... </a>

URL

url(r'^products/tools/(?P<slug>[^\.]+)/$', tool_detail, name='tool_detail'),

Ugh...see how /tools/ is hardcoded?

Thank you for your help.

Upvotes: 0

Views: 1938

Answers (2)

JClarke
JClarke

Reputation: 808

URL

# query by primary key.
url(r'^products/(?P<category>[0-9]+)/(?P<slug>[^\.]+)/$', tool_detail, name='tool_detail'),

# query by the name.
url(r'^products/(?P<category>[\w]+)/(?P<slug>[^\.]+)/$', tool_detail, name='tool_detail'),

View

def tool_detail(request, **kwargs):
    tool = get_object_or_404(Tool, slug=kwargs.get('slug'))
    part = get_object_or_404(Part)
    return render(request, 'tool_detail.html', {'tool': tool, 'part': part})

Should work it isn't tested.

Upvotes: 2

Son Lam
Son Lam

Reputation: 1320

In url only pass on parameter slug, but on url tag you pass two paramter. Only modify like as Templates

  <a href="{% url 'tool_detail' t.slug %}" ... </a>

If slug is int we can change url

    url(r'^products/tools/(?P<slug>[0-9]+)/$', tool_detail, name='tool_detail'),

Some example about how to pass dynamic parameter on url tag https://docs.djangoproject.com/en/1.9/intro/tutorial04/

Upvotes: 1

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