Reputation:
int main()
{
...
if(!fork())
{
execvp(cmdName,cmdParam);
}
printf("In main()...");
return(0);
}
Upvotes: 0
Views: 7442
Reputation: 14452
For your first question:
Use waitpid(2) like this:
int pid = fork();
if (!pid)
{
execvp(cmdName, cmdParam);
}
waitpid(pid, NULL, 0);
printf("Resuming main()...\n");
For the second part: all exec function calls take the process over (none of them return)
Upvotes: 3
Reputation: 27222
As noted you need to save the value of the fork call. You should really use more than an if on the fork. There are three cases:
0: you're the parent and got a child PID back
You really want to know about case 3, it'll ruin your whole day. (also the exec call)
int main() {
int pid = fork();
if(-1 == pid) {
fprintf(stderr, "Big problems forking %s\n", strerror(errno);
exit(-1);//or whatever
}
else if (0 == pid) {
if (-1 == execvp(cmdName,cmdParam)) {
//like above, get some output about what happened
}
}
//no need to else here, execvp shouldn't return
// if it does you've taken care of it above
waitpid(pid, NULL, 0);
printf("Resuming main()...");
}
return(0); }
Upvotes: 3
Reputation: 1795
You need to store the return value of fork()
, which returns a different value to each executable (0 if you are the child PID if you are the parent), and then you need to do a waitpid
Upvotes: 1
Reputation: 25491
In the parent process, fork
returns the PID of the child process, so you can store that in a variable, and then use waitpid
to wait for the child process to terminate.
Not really - the new child process created by fork
is a duplicate of the parent, and execvp
then replaces its process image with a new image. Effectively you initially have two 'copies' of the parent, one of which then 'becomes' the new program.
Upvotes: 3