CODEWITHSUNDEEP
javascriptarrays
Vaibhav Luthra
Vaibhav Luthra

Reputation: 55

Reversing certain number of elements in an array javascript

I am working on a code where I need to reverse certain no of elements in an array and rest should remain same. For example is an array has values of 1,2,3,4,5,6 and I have to reverse 4 elements of it then output should be 4,3,2,1,5,6. I am using below code to achieve this but getting error, please suggest.

function reverseArray(n, a) {
  var interimArray1 = [];
  //var interimArray2=[];
  //var finalArray=[];
  for (var i < n; i >= 0; i--) {
    interimArray1.push[a[i]];
  }
  for (var i = n; i < a.length; i++) {
    interimArray1.push[a[i]];
  }
  for (var i = 0; i < interimArray1.length; i++) {
    console.log(interimArray1[i]);
  }
}

var arr = [1, 2, 3, 4, 5, 6];
var num = 4;

reverseArray(num, arr);

Upvotes: 1

Views: 70

Answers (6)

mareoraft
mareoraft

Reputation: 3902

The error in your code is that you intend to call the push method on a[i] like so:

interimArray1.push(a[i]);

but instead you write:

interimArray1.push[a[i]];

You make that mistake twice. To give arguments to the push method, you must use round parenthesis ().

With that fixed, you will see that your code works perfectly.

Upvotes: 2

Mohamed Fathy Mahmoud Elshmakh
Mohamed Fathy Mahmoud Elshmakh

Reputation: 64

This is the answer you can test it.

        function reverseArray(n, a) {
            var interimArray1 = [];

            for (var i = 0; i < a.length; i++) {
              interimArray1.push(a[i]);
            }
        for (var i = num; i >=0; i--) {
            interimArray1[i-1] = a[n - i];
        }
        for (var i = 0; i < interimArray1.length; i++) {
            console.log(interimArray1[i]);
        }
        }

        var arr = [1, 2, 3, 4, 5, 6];
        var num = 4;

        reverseArray(num, arr);

Upvotes: 0

Mathieu Lavoie
Mathieu Lavoie

Reputation: 41

This is working :

I'm sure there are faster ways of doing it. Also, it will only work for elements at the beginning of the array but you can adjust the function for what you want to achieve.

var reverseArray = function(arr,elementsToReverse) {
  var tempArrayRev = [];
  var tempArray = [];
  for (var i=0;i<arr.length;i++) {
     if (i < elementsToReverse) {
       tempArrayRev[i] = arr[i];
     } else {
       tempArray.push(arr[i]);
     }
  }
    return tempArrayRev.reverse().concat(tempArray);
}

var array = [1,2,3,4,5,6];


document.getElementById('arrayOutput').innerHTML += reverseArray(array,4);
<div id="arrayOutput">Array :<br></div>

Upvotes: 0

RobG
RobG

Reputation: 147363

Lots of hints but you seem to be missing them. ;-)

You need to assign an initial value to i, so:

for (var i = n; ... )
===========^

Also, you need to use () to call functions, not [], so:

interimArray1.push(a[i]);
==================^====^

Same in the following for block. Otherwise, the code works though it's more verbose than it needs to be.

Upvotes: 0

Tushar
Tushar

Reputation: 87203

You can use Array#slice, Array#splice as follow.

function partialReverse(arr, num, from = 0) {
    var slicedArr = arr.slice(from, num + from);
    
    arr.splice(from, num); // Remove `num` items from array
    arr.splice(from, 0, ...slicedArr.reverse()); // Add `num` reversed items

    return arr;
}

var arr = [1, 2, 3, 4, 5, 6];
console.log(partialReverse(arr, 4, 0)); // Reverse four items from `arr` starting from 0th index
console.log(partialReverse(arr, 4, 1)); // Reverse four items from `arr` starting from 1st index

Upvotes: 0

Spaceman
Spaceman

Reputation: 1339

You could use something like this.

function reverseArray(n, arrIn) {
    // Splice splits the array in 2 starting at 0 index going n long
    var arrOut = arrIn.splice(0,n);
    // reverse is pretty straight forward
    arrOut = arrOut.reverse();
    // Concat joins the two together
    return arrOut.concat(arrIn);
}

Upvotes: -1

Related Questions