CODEWITHSUNDEEP
pythonpython-2.7
avbirm
avbirm

Reputation: 105

inputting a list of values into a function

I am making a program that determines if a triangle is obtuse(O),acute(A) or right(R)

Enter in the length of angles
>>> 3 8 9
TypeError: pythag() takes exactly 3 arguments (1 given)

I understand why I'm getting the error but what I'm trying to do is somehow loop the values of the list into the function and then call the function. 

input = raw_input("Enter in the length of angles\n>>> ") #>>> 3 8 9
lst = input.split() #splits the input into a list by whitespace
for i in lst: #converts the values in the list to integers
    int(i)

def pythag(a,b,c): #function to perform calculation
    if a^2 + b^2 != c^2:
        if c^2 > a^2 or b^2:
            return "A"
        else:
            return "O"
    else:
        return "R"

pythag(lst)

Any suggestions?

Thanks in advance.

Upvotes: 0

Views: 61

Answers (1)

bereal
bereal

Reputation: 34282

First of all, int(i) does nothing to the original list, so it still contains strings. Second, which is where your exception happens, is that you are still passing a single argument to the function.

lst = [int(i) for i in lst]  # convert the input
pythag(*lst)  # same as pythag(lst[0], lst[1], ...)

Upvotes: 3

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