CODEWITHSUNDEEP
cmallocposixbuffer
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Reputation: 4374

Doubt in malloc. C (Linux)

In the following code,what is the meaning of buf = malloc(n * sizeof(char));

is n*sizeof(char) necessary,if yes.. please elaborate.

int n;

char* buf;

fstat(fd, &fs);

n = fs.st_size;

buf = malloc(n * sizeof(char));

EDIT1 And What if I write (n*sizeof(double))

Upvotes: 3

Views: 435

Answers (2)

linuxuser27
linuxuser27

Reputation: 7353

The malloc function allocates bytes and takes as input the number of bytes you would like to allocate. The sizeof operator returns the number of bytes for a given type. In this case a char is 1 byte, but in the case of an int it is most likely 4 bytes or double is most likely 8 bytes. The expression n * sizeof(char) converts the number of char into the number of bytes that are desired.

In the case illustrated, using char, computing the number of bytes is probably not needed, but it should be done as it helps to convey your intent.

What the expression is doing is allocating the desired amount of memory needed to hold at most n number of char's and returning you a pointer, buf, to the beginning of that allocated memory.

Upvotes: 6

codaddict
codaddict

Reputation: 455122

The ISO standard defines a byte as the same size as a char.

You never need sizeof(char) for malloc

Upvotes: 1

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