CODEWITHSUNDEEP
typescript
JuKe
JuKe

Reputation: 673

type definition if a function that when called pollutes the global namespace

Let's say we have a plain javascript constructor function that has a static property called extend. If we pass a string into this method (extend) it will create a new constructor function on the window object.

Here is a implementation of that: https://canjs.com/docs/can.Construct.extend.html

Here is my type definition:

declare module "can/construct/" {

    interface ConstructFactory {
        new(): Construct;
    }

    class Construct {
        constructor();
        static extend(name: string): ConstructFactory;
        static extend(name: string, staticProperties: {}): ConstructFactory;
        static extend(name: string, staticProperties: {}, instanceProperties: {}): ConstructFactory;
        static extend(staticProperties: {}, instanceProperties: {}): ConstructFactory;
        static extend(instanceProperties: {}): ConstructFactory;
    }
}

My typescript file looks like:

import {Construct} from "can/construct/";
Construct.extend('Foo');
let foobar = new Foo();

But i get an error: TS2304: Cannot find name 'Foo'.

How can I let typescript know that Foo is created in the extend method?

Upvotes: 0

Views: 121

Answers (1)

basarat
basarat

Reputation: 276303

how can i letting typescript know that Foo is created in the extend method

You cannot declare a function that when called pollutes the global namespace. That feels like a bad idea and so I doubt it will ever be supported by TypeScript.

Note: you can declare a function that will return a constructor variable for you. But this is not the question you are asking.

Upvotes: 2

Related Questions