CODEWITHSUNDEEP
regexnotepad++
zephyr
zephyr

Reputation: 2332

Find and replace parts of matched string in Notepad++

I have something in a text file that looks like '%r'%XXXX, where the XXXX represents some name at the end. Examples include '%r'%addR or '%r'%removeA. I can match these patterns using regex '%r'%\w+. What I would like to replace this with is '{!r}'.format(XXXX). Note that the name has to stay the same in the replace so I'd get '{!r}.format(addR) or '{!r}.format(removeA). Is there a way to replace parts of the matched string in this way while retaining the unknown variable name pulled out with \w+ in the regex search?

I'm specifically looking for a solution using the find and replace features in Notepad++.

Upvotes: 1

Views: 2074

Answers (2)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626861

You can use

'%r'%(\w+)

and replace with '{!r}.format\(\1\)

The '%r'%(\w+) pattern contains a pair of unescaped parentheses that create a capturing group. Inside the replacement pattern, we use a \1 backreference to restore that value.

NOTE: The ( and ) in the replacement must be escaped because otherwise they are treated as Boost conditional replacement pattern functional characters.

See more on capturing groups and backreferences.

enter image description here

Upvotes: 2

Smandoli
Smandoli

Reputation: 7019

Search on:

'%r'%(XXXX)

Replace with:

Whatever You like \1

\1 will match the first set of grouping parentheses.

Upvotes: 0

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