CODEWITHSUNDEEP
javascriptnode.jsunderscore.js
Danilo
Danilo

Reputation: 382

Search JSON values in array using underscore

I have the file default.json:

{
    "IPs": {
        "ip1": "192.168.0.1",
        "ip2": "192.168.0.2",
        "ip3": "192.168.0.3"
    }
}

My code:

var _      = require('underscore'),
    config = require('default.json')

var array  = ['192.168.0.1', '192.168.0.2']

//search array in IPs

How can I search values of array in IPs (ip1, ip2, ip3) and whenever it's true, call a function? Preferably using an underscore function.

Upvotes: 0

Views: 670

Answers (2)

Danilo
Danilo

Reputation: 382

I used this solution (with underscore):

File default.json

    {
        "IPs": {
            "ip1": "192.168.0.1",
            "ip2": "192.168.0.2",
            "ip3": "192.168.0.3"
        }
    }

The code:

var _      = require('underscore'),
    config = require('default.json')

var array = ['192.168.0.1', '192.168.0.2']
var IPs   = config.IPs

_.each(IPs, function(e, k){
    //if find IPs in array
    if(array.indexOf(e) > -1)
        //do something
    else
        //do something
})

Upvotes: 0

Rob Brander
Rob Brander

Reputation: 3781

Assuming you fix default.json to be like this:

"IPs": {
    ip1: "192.168.0.1",
    ip2: "192.168.0.2",
    ip3: "192.168.0.3"
}

You can then search for the IPs matching

var foundIPs = Object.keys(config.IPs).filter(function(name) {
  // name will be something like 'ip1', 'ip2', or 'ip3'
  var currIP = config.IPs[name]; // eg. currIP = "192.168.0.1"
  var inArray = array.indexOf(currIP) > -1;
  return inArray;
});
var foundIP = foundIPs.length > 0;

Upvotes: 1

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