CODEWITHSUNDEEP
boolean-logicboolean-algebra
Salma Hassan
Salma Hassan

Reputation: 9

Simlification using boolean algebra

What is the simplest form of A'B'C' + A'B'C + A'BC' + AB'C' ? I've tried doing it using both K-map and Boolean algebra rules but they gave me different answers!

Upvotes: 0

Views: 136

Answers (2)

Axel Kemper
Axel Kemper

Reputation: 11332

What about this?

A'B' + A'C' + B'C'

or

A'B' + (AB)'C'

The Karnaugh map:

             bc
       00  01  11  10
      +---+---+---+---+
   0  | 1 | 1 | 0 | 1 |
a     +---+---+---+---+
   1  | 1 | 0 | 0 | 0 |
      +---+---+---+---+

Upvotes: 0

Mark Sholund
Mark Sholund

Reputation: 1312

The simplest form that I can find is

A'B'C' + A'B'C + A'BC' + AB'C'
A'B'(C'+C) + (A'B + AB')C'
A'B'(1) + (A'B + AB')C'
A'B' + (A'B + AB')C'

which is

A'B' + (A XOR B)C'

Upvotes: 1

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