CODEWITHSUNDEEP
pythonsplit
anon
anon

Reputation: 25

How to split characters of a text file.

I have to split characters from a text file which looks like this:

87965202,3127C4

87965221,2496B3

87965208,6703D3

87965155,5930B4

I have separated the lines at the commas. I just need some help with splitting the second part of the line into three separate characters. i.e. "3127", "C", "4"

This is my code so far:

for line in inputFile2:
        parts = line.split(",")
        info = parts[1]

Upvotes: 0

Views: 1054

Answers (6)

J Mascis
J Mascis

Reputation: 103

You are talking about this: info[8:12] ?

Upvotes: 0

Pedru
Pedru

Reputation: 1460

Or with a regular expression

import re
r = re.compile('([0-9]{4})([A-Z])([0-9])')
print r.findall('5930B4')
print r.findall('3127C4')

gives

[('5930', 'B', '4')]
[('3127', 'C', '4')]

Upvotes: 1

ΦXocę 웃 Пepeúpa ツ
ΦXocę 웃 Пepeúpa ツ

Reputation: 48297

Use regex for that:

Example:

info = parts[1]
info = "3127C4"
//use regex to match the no numeric char
indexChar = re.search("\D", info)
slice1 = values[0:indexChar]
slice2 = values[indexChar]
slice3 = values[indexChar:]

dont forget to import re

Upvotes: 0

GoingMyWay
GoingMyWay

Reputation: 17478

slice the string

info = []
for line in inputFile2:  
    parts = line.split(",")
    info.append([parts[0], parts[1][:4], parts[1][4:5], parts[1][5:]])

Upvotes: -1

Keatinge
Keatinge

Reputation: 4321

secondHalf = "5930B4"


#slicing format is string[start:end:step]
initialNumber = secondHalf[0:4] #start at character 0 and end at character 4
middleLetter = secondHalf[4:5] #start at character 4 and end at character 5
endingNumber = secondHalf[-1:] #start from the last character

print(initialNumber, middleLetter, endingNumber)
#output: 5930 B 4

Upvotes: 0

Robᵩ
Robᵩ

Reputation: 168856

If the 2nd part will always be of the form NNNNAN, then you can use slicing:

info = '2496B3'
info = info[0:4],info[4:5],info[5:6]
print(info)
# ('2496', 'B', '3')

If the pattern needs to be more general, try a regular expression:

import re
info = '249678ABBZ3'
re.split('([A-Z]+)', info)
# ['249678', 'ABBZ', '3']

Upvotes: 1

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