Reputation: 702
I am just trying out different algorithms for practice and I came across this problem for which I have to generate all the subsets of a given set of elements (non-duplicate).
the naive solution for this is using bitmasking technique. But that has an exponential time complexity i.e O(2^n). In the worst case scenario, value of n can be upto 100000
so in this scenario O(n^2) solution is not very eddicient.
I am just wondering if there is any other more efficient algorithm which can solve this in ~O(n^2)?
Upvotes: 0
Views: 1559
Reputation: 51998
While there is clearly no polynomial time way to generate all subsets of an n
element set, some ways of doing so are more efficient than others. In particular, if you use a Gray code you can go from 1 subset to another by adding or removing a single element from successive subsets. This would make e.g. brute-force knapsack solutions noticeably more efficient (for e.g. n around 30 or smaller).
Upvotes: 3
Reputation: 5629
If you want to for example print all the subsets or store them explicitly anywhere there is no such algorithm. Notice that there are 2^n
subsets of a set of n
elements and simply enumerating them requires an exponential time
.
Upvotes: 3