CODEWITHSUNDEEP
phparrayscountpredicate
JoakimSjo
JoakimSjo

Reputation: 1786

Count value of key in array

I have this array:

Array
(
    [boks_1] => Array
        (
            [tittel] => Test
            [innhold] =>      This is a test text
            [publish] => 2
        )

    [boks_2] => Array
        (
            [tittel] => Test 3
            [innhold] => This is a text test
            [publish] => 1
        )

    [boks_3] => Array
        (
            [tittel] => Kontakt oss
            [innhold] => This is a test text
            [publish] => 1
        )
)

How can I use PHP count() to count how many times [publish] => 1 appears in my array? I am going to use the value to control the width of divs in a flexbox container.

Upvotes: 3

Views: 105

Answers (3)

AbraCadaver
AbraCadaver

Reputation: 78994

For fun:

$count = array_count_values(array_column($array, 'publish'))[1];
  • Get an array of the publish keys
  • Count the values
  • Get the count of the 1s using index [1]

O.K. more fun:

$count = count(array_keys(array_column($array, 'publish'), 1));
  • Get an array of the publish keys
  • Get array keys where the value is 1
  • Count the array

NOTE: You might want to pass true as the third argument to array_keys() to be more accurate and use '1' instead of 1 if the 1s are strings and not integers.

Upvotes: 6

ameenulla0007
ameenulla0007

Reputation: 2683

$newArray = array_filter($booksArray, function($bookDet) { if($bookDet["publish"]==1) { return $bookDet; } });
$getCount = count($newArray);

use array_filter to filter out only required array details, and get a count of it.

this could be the simplest, and performance oriented as well, as it won't loop.

Upvotes: 3

Unex
Unex

Reputation: 1757

this should solve your problem : 

$array = array(); //This is your data sample

$counter = 0; //This is your counter
foreach ($array as $key => $elem) {
    if (array_key_exists('publish', $elem) && $elem['publish'] === 1) {
        $counter += $elem['publish'];
    }
}

hope this'll help,

Upvotes: 1

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