CODEWITHSUNDEEP
cformatintegerprintfhex
user188276
user188276

Reputation:

How can I display hexadecimal numbers in C?

I have a list of numbers as below:

0, 16, 32, 48 ...

I need to output those numbers in hexadecimal as:

0000,0010,0020,0030,0040 ...

I have tried solution such as:

printf("%.4x", a); // Where a is an integer

But the result that I got was:

0000, 0001, 0002, 0003, 0004 ...

I think I'm close there. How can I fix it?

I'm not so good at printf in C.

Upvotes: 62

Views: 344884

Answers (4)

codaddict
codaddict

Reputation: 455132

Try:

printf("%04x",a);
  • 0 - Left-pads the number with zeroes (0) instead of spaces, where padding is specified.
  • 4 (width) - Minimum number of characters to be printed. If the value to be printed is shorter than this number, the result is right justified within this width by padding on the left with the pad character. By default this is a blank space, but the leading zero we used specifies a zero as the pad char. The value is not truncated even if the result is larger.
  • x - Specifier for hexadecimal integer.

More here

Upvotes: 138

zeilja
zeilja

Reputation: 509

I use it like this:

printf("my number is 0x%02X\n",number);
// Output: my number is 0x4A

Just change number "2" to any number of characters you want to print ;)

Upvotes: 9

hmofrad
hmofrad

Reputation: 1902

You can use the following snippet code:

#include<stdio.h>
int main(int argc, char *argv[]){
    unsigned int i;
    printf("decimal  hexadecimal\n");
    for (i = 0; i <= 256; i+=16)
        printf("%04d     0x%04X\n", i, i);
    return 0;
}

It prints both decimal and hexadecimal numbers in 4 places with zero padding.

Upvotes: 1

loxxy
loxxy

Reputation: 13151

Your code has no problem. It does print the way you want. Alternatively, you can do this:

printf("%04x",a);

Upvotes: 2

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