Reputation: 5
I'm trying to a postfix expression calculator but I stuck on a problem. The calculator returns the wrong answer and I don't know why. I've followed the program line by line and nothing should be wrong. heres my code so far:
char expression[] = {"321*+"};
int number1, number2;
char *pExpression = &expression[0];
char symbole;
PileInt pile;
pile.init(5);
while(*pExpression){
symbole = *pExpression;
if(symbole == '+' || symbole == '-' || symbole == '*' || symbole == '/'){
switch (symbole){
case '+':
number2 = pile.pop();
number1 = pile.pop();
pile.push(number1 + number2);
break;
case '-':
number2 = pile.pop();
number1 = pile.pop();
pile.push(number1 - number2);
break;
case '*':
number2 = pile.pop();
number1 = pile.pop();
pile.push(number1 * number2);
break;
case '/':
number2 = pile.pop();
number1 = pile.pop();
pile.push(number1 / number2);
break;
}
} else pile.push(symbole);
pExpression++;
}
cout<<pile.pop()<<endl;
and heres the methods:
void PileInt::init(int taille){ //Methode pour initialiser une pile d'entier
_addr = new int [ _taille = taille ];
assert( _addr != 0 );
_sommet = 0;
}
void PileInt::push(int n){ //Methode pour mettre un entier au dessus de la pile
if ( ! pleine() )
_addr[ _sommet++ ] = n;
}
int PileInt::pop(){ //Methode pour sortir l'entier au dessus de la pile
return ( ! vide() ) ? _addr[ --_sommet ] : 0;
}
int PileInt::top(){
if( ! vide() )
return (_sommet - 1);
}
expression: 321*+ Console returns 2501, it should return 5. Thank you in advance.
Upvotes: 0
Views: 6835
Reputation: 59997
When you have a number - you are pushing on its ASCII value.
You need to push on its value so change
pile.push(symbole);
to
pile.push(symbole - '0');
Upvotes: 4