CODEWITHSUNDEEP
phpdatetimeminute
Tom Smykowski
Tom Smykowski

Reputation: 26089

How to get time difference in minutes in PHP

How to calculate minute difference between two date-times in PHP?

Upvotes: 346

Views: 781222

Answers (21)

nimrod
nimrod

Reputation: 5732

Here is a simple one-liner:

$start = new DateTime('yesterday');
$end = new DateTime('now');
$diffInMinutes = iterator_count(new \DatePeriod($start, new \DateInterval('PT1M'), $end));

Upvotes: 1

Şafak Gezer
Şafak Gezer

Reputation: 4007

DateTime::diff is cool, but awkward for this sort of calculations that require a single unit result. Manually subtracting the timestamps works better:

$date1 = new DateTime('2020-09-01 01:00:00');
$date2 = new DateTime('2021-09-01 14:00:00');
$diff_mins = abs($date1->getTimestamp() - $date2->getTimestamp()) / 60;

Upvotes: 25

Hamza Qureshi
Hamza Qureshi

Reputation: 202

try this

$now = \Carbon\Carbon::now()->toDateString(); // get current time 
             $a = strtotime("2012-09-21 12:12:22"); 
             $b = strtotime($now);
             $minutes = ceil(($a - $b) / 3600); it will get ceiling value

Upvotes: -2

Udith Chandrarathna
Udith Chandrarathna

Reputation: 324

Another simple way to calculate the difference in minutes. Please note this is a sample for calculating within a 1-year range. for more details click here

$origin = new DateTime('2021-02-10 09:46:32');
$target = new DateTime('2021-02-11 09:46:32');
$interval = $origin->diff($target);
echo (($interval->format('%d')*24) + $interval->format('%h'))*60; //1440 (difference in minutes)

Upvotes: 1

Soner from The Ottoman Empire
Soner from The Ottoman Empire

Reputation: 20891

$date1=date_create("2020-03-15");
$date2=date_create("2020-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");

For detailed format specifiers, visit the link.

Upvotes: 2

Raj Nandan Sharma
Raj Nandan Sharma

Reputation: 3852

I wrote this function for one my blog site(difference between a past date and server's date). It will give you an output like this

"49 seconds ago", "20 minutes ago", "21 hours ago" and so on

I have used a function that would get me the difference between the date passed and the server's date.

<?php

//Code written by purpledesign.in Jan 2014
function dateDiff($date)
{
    $mydate= date("Y-m-d H:i:s");
    $theDiff="";
    //echo $mydate;//2014-06-06 21:35:55
    $datetime1 = date_create($date);
    $datetime2 = date_create($mydate);
    $interval = date_diff($datetime1, $datetime2);
    //echo $interval->format('%s Seconds %i Minutes %h Hours %d days %m Months %y Year    Ago')."<br>";
    $min=$interval->format('%i');
    $sec=$interval->format('%s');
    $hour=$interval->format('%h');
    $mon=$interval->format('%m');
    $day=$interval->format('%d');
    $year=$interval->format('%y');
    if($interval->format('%i%h%d%m%y')=="00000") {
        //echo $interval->format('%i%h%d%m%y')."<br>";
        return $sec." Seconds";
    } else if($interval->format('%h%d%m%y')=="0000"){
        return $min." Minutes";
    } else if($interval->format('%d%m%y')=="000"){
        return $hour." Hours";
    } else if($interval->format('%m%y')=="00"){
        return $day." Days";
    } else if($interval->format('%y')=="0"){
        return $mon." Months";
    } else{
        return $year." Years";
    }    
}
?>

Save it as a file suppose "date.php". Call the function from another page like this

<?php
 require('date.php');
 $mydate='2014-11-14 21:35:55';
 echo "The Difference between the server's date and $mydate is:<br> ";
 echo dateDiff($mydate);
?>

Of course you can modify the function to pass two values.

Upvotes: 13

hriziya
hriziya

Reputation: 1172

This is how I displayed "xx times ago" in php > 5.2 .. here is more info on DateTime object

//Usage:
$pubDate = $row['rssfeed']['pubDates']; // e.g. this could be like 'Sun, 10 Nov 2013 14:26:00 GMT'
$diff = ago($pubDate);    // output: 23 hrs ago

// Return the value of time different in "xx times ago" format
function ago($timestamp)
{

    $today = new DateTime(date('y-m-d h:i:s')); // [2]
    //$thatDay = new DateTime('Sun, 10 Nov 2013 14:26:00 GMT');
    $thatDay = new DateTime($timestamp);
    $dt = $today->diff($thatDay);

    if ($dt->y > 0){
        $number = $dt->y;
        $unit = "year";
    } else if ($dt->m > 0) {
        $number = $dt->m;
        $unit = "month";
    } else if ($dt->d > 0) {
        $number = $dt->d;
        $unit = "day";
    } else if ($dt->h > 0) {
        $number = $dt->h;
        $unit = "hour";
    } else if ($dt->i > 0) {
        $number = $dt->i;
        $unit = "minute";
    } else if ($dt->s > 0) {
        $number = $dt->s;
        $unit = "second";
    }
    
    $unit .= $number  > 1 ? "s" : "";
 
    $ret = $number." ".$unit." "."ago";
    return $ret;
}

Upvotes: 11

MB_18
MB_18

Reputation: 2251

Subtract the times and divide by 60.

Here is an example which calculate elapsed time from 2019/02/01 10:23:45 in minutes:

$diff_time=(strtotime(date("Y/m/d H:i:s"))-strtotime("2019/02/01 10:23:45"))/60;

Upvotes: 8

Rahilkhan Pathan
Rahilkhan Pathan

Reputation: 524

<?php
$start = strtotime('12:01:00');
$end = strtotime('13:16:00');
$mins = ($end - $start) / 60;
echo $mins;
?>

Output:

75

Upvotes: 32

Sumit Kumar Gupta
Sumit Kumar Gupta

Reputation: 2364

I found so many solution but I never got correct solution. But i have created some code to find minutes please check it.

<?php

  $time1 = "23:58";
  $time2 = "01:00";
  $time1 = explode(':',$time1);
  $time2 = explode(':',$time2);
  $hours1 = $time1[0];
  $hours2 = $time2[0];
  $mins1 = $time1[1];
  $mins2 = $time2[1];
  $hours = $hours2 - $hours1;
  $mins = 0;
  if($hours < 0)
  {
    $hours = 24 + $hours;
  }
  if($mins2 >= $mins1) {
        $mins = $mins2 - $mins1;
    }
    else {
      $mins = ($mins2 + 60) - $mins1;
      $hours--;
    }
    if($mins < 9)
    {
      $mins = str_pad($mins, 2, '0', STR_PAD_LEFT);
    }
    if($hours < 9)
    {
      $hours =str_pad($hours, 2, '0', STR_PAD_LEFT);
    }
echo $hours.':'.$mins;
?>

It gives output in hours and minutes for example 01 hour 02 minutes like 01:02

Upvotes: 0

Ali Han
Ali Han

Reputation: 529

My solution to find the difference between two dates is here. With this function you can find differences like seconds, minutes, hours, days, years and months.

function alihan_diff_dates($date = null, $diff = "minutes") {
 $start_date = new DateTime($date);
 $since_start = $start_date->diff(new DateTime( date('Y-m-d H:i:s') )); // date now
 print_r($since_start);
 switch ($diff) {
    case 'seconds':
        return $since_start->s;
        break;
    case 'minutes':
        return $since_start->i;
        break;
    case 'hours':
        return $since_start->h;
        break;
    case 'days':
        return $since_start->d;
        break;      
    default:
        # code...
        break;
 }
}

You can develop this function. I tested and works for me. DateInterval object output is here: 

/*
DateInterval Object ( [y] => 0 [m] => 0 [d] => 0 [h] => 0 [i] => 5 [s] => 13 [f] => 0 [weekday] => 0 [weekday_behavior] => 0 [first_last_day_of] => 0 [invert] => 0 [days] => 0 [special_type] => 0 [special_amount] => 0 [have_weekday_relative] => 0 [have_special_relative] => 0 ) 
*/

Function Usage:

$date = the past date, $diff = type eg: "minutes", "days", "seconds"

$diff_mins = alihan_diff_dates("2019-03-24 13:24:19", "minutes");

Good Luck.

Upvotes: 2

Gyandeep Sharma
Gyandeep Sharma

Reputation: 2327

This will help....

function get_time($date,$nosuffix=''){
    $datetime = new DateTime($date);
    $interval = date_create('now')->diff( $datetime );
    if(empty($nosuffix))$suffix = ( $interval->invert ? ' ago' : '' );
    else $suffix='';
    //return $interval->y;
    if($interval->y >=1)        {$count = date(VDATE, strtotime($date)); $text = '';}
    elseif($interval->m >=1)    {$count = date('M d', strtotime($date)); $text = '';}
    elseif($interval->d >=1)    {$count = $interval->d; $text = 'day';} 
    elseif($interval->h >=1)    {$count = $interval->h; $text = 'hour';}
    elseif($interval->i >=1)    {$count = $interval->i; $text = 'minute';}
    elseif($interval->s ==0)    {$count = 'Just Now'; $text = '';}
    else                        {$count = $interval->s; $text = 'second';}
    if(empty($text)) return '<i class="fa fa-clock-o"></i> '.$count;
    return '<i class="fa fa-clock-o"></i> '.$count.(($count ==1)?(" $text"):(" ${text}s")).' '.$suffix;     
}

Upvotes: 0

besimple
besimple

Reputation: 443

A more universal version that returns result in days, hours, minutes or seconds including fractions/decimals:

function DateDiffInterval($sDate1, $sDate2, $sUnit='H') {
//subtract $sDate2-$sDate1 and return the difference in $sUnit (Days,Hours,Minutes,Seconds)
    $nInterval = strtotime($sDate2) - strtotime($sDate1);
    if ($sUnit=='D') { // days
        $nInterval = $nInterval/60/60/24;
    } else if ($sUnit=='H') { // hours
        $nInterval = $nInterval/60/60;
    } else if ($sUnit=='M') { // minutes
        $nInterval = $nInterval/60;
    } else if ($sUnit=='S') { // seconds
    }
    return $nInterval;
} //DateDiffInterval

Upvotes: 8

yussan
yussan

Reputation: 2327

It worked on my programs, i'am using date_diff, you can check date_diff manual on here.

$start = date_create('2015-01-26 12:01:00');
$end = date_create('2015-01-26 13:15:00');
$diff=date_diff($end,$start);
print_r($diff);

You get results what do you want.

Upvotes: 18

Oli
Oli

Reputation: 239810

Subtract the past most one from the future most one and divide by 60.

Times are done in Unix format so they're just a big number showing the number of seconds from January 1, 1970, 00:00:00 GMT

Upvotes: 109

Veerendra
Veerendra

Reputation: 2622

function date_getFullTimeDifference( $start, $end )
{
$uts['start']      =    strtotime( $start );
        $uts['end']        =    strtotime( $end );
        if( $uts['start']!==-1 && $uts['end']!==-1 )
        {
            if( $uts['end'] >= $uts['start'] )
            {
                $diff    =    $uts['end'] - $uts['start'];
                if( $years=intval((floor($diff/31104000))) )
                    $diff = $diff % 31104000;
                if( $months=intval((floor($diff/2592000))) )
                    $diff = $diff % 2592000;
                if( $days=intval((floor($diff/86400))) )
                    $diff = $diff % 86400;
                if( $hours=intval((floor($diff/3600))) )
                    $diff = $diff % 3600;
                if( $minutes=intval((floor($diff/60))) )
                    $diff = $diff % 60;
                $diff    =    intval( $diff );
                return( array('years'=>$years,'months'=>$months,'days'=>$days, 'hours'=>$hours, 'minutes'=>$minutes, 'seconds'=>$diff) );
            }
            else
            {
                echo "Ending date/time is earlier than the start date/time";
            }
        }
        else
        {
            echo "Invalid date/time data detected";
        }
}

Upvotes: 8

Yubraj Pokharel
Yubraj Pokharel

Reputation: 485

I think this will help you 

function calculate_time_span($date){
    $seconds  = strtotime(date('Y-m-d H:i:s')) - strtotime($date);

        $months = floor($seconds / (3600*24*30));
        $day = floor($seconds / (3600*24));
        $hours = floor($seconds / 3600);
        $mins = floor(($seconds - ($hours*3600)) / 60);
        $secs = floor($seconds % 60);

        if($seconds < 60)
            $time = $secs." seconds ago";
        else if($seconds < 60*60 )
            $time = $mins." min ago";
        else if($seconds < 24*60*60)
            $time = $hours." hours ago";
        else if($seconds < 24*60*60)
            $time = $day." day ago";
        else
            $time = $months." month ago";

        return $time;
}

Upvotes: 12

Muhammad
Muhammad

Reputation: 3250

another way with timezone. 

$start_date = new DateTime("2013-12-24 06:00:00",new DateTimeZone('Pacific/Nauru'));
$end_date = new DateTime("2013-12-24 06:45:00", new DateTimeZone('Pacific/Nauru'));
$interval = $start_date->diff($end_date);
$hours   = $interval->format('%h'); 
$minutes = $interval->format('%i');
echo  'Diff. in minutes is: '.($hours * 60 + $minutes);

Upvotes: 16

mike
mike

Reputation: 5185

The answers above are for older versions of PHP. Use the DateTime class to do any date calculations now that PHP 5.3 is the norm. Eg.

$start_date = new DateTime('2007-09-01 04:10:58');
$since_start = $start_date->diff(new DateTime('2012-09-11 10:25:00'));
echo $since_start->days.' days total<br>';
echo $since_start->y.' years<br>';
echo $since_start->m.' months<br>';
echo $since_start->d.' days<br>';
echo $since_start->h.' hours<br>';
echo $since_start->i.' minutes<br>';
echo $since_start->s.' seconds<br>';

$since_start is a DateInterval object. Note that the days property is available (because we used the diff method of the DateTime class to generate the DateInterval object).

The above code will output:

1837 days total
5 years
0 months
10 days
6 hours
14 minutes
2 seconds

To get the total number of minutes:

$minutes = $since_start->days * 24 * 60;
$minutes += $since_start->h * 60;
$minutes += $since_start->i;
echo $minutes.' minutes';

This will output:

2645654 minutes

Which is the actual number of minutes that has passed between the two dates. The DateTime class will take daylight saving (depending on timezone) into account where the "old way" won't. Read the manual about Date and Time http://www.php.net/manual/en/book.datetime.php

Upvotes: 504

user38526
user38526

Reputation: 3885

Here is the answer:

$to_time = strtotime("2008-12-13 10:42:00");
$from_time = strtotime("2008-12-13 10:21:00");
echo round(abs($to_time - $from_time) / 60,2). " minute";

Upvotes: 384

Tom
Tom

Reputation: 8127

<?php
$date1 = time();
sleep(2000);
$date2 = time();
$mins = ($date2 - $date1) / 60;
echo $mins;
?>

Upvotes: 43

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