CODEWITHSUNDEEP
carrayscharacter
gluttony47
gluttony47

Reputation: 91

explain me what is happening here [c Character array + integer]

i saw this code :

#include <stdio.h>

int main()
{
    char string[] = "       *      *     **   * * *  *";
    int line = 6, stop = 0, len = 8;
    for(line = 6; line > 0;line--){
        printf("%.*s\n", len, string + stop);
        stop = stop + len;
        --len;
    }
    return 0;
}

string is a character array, stop is an integer. how is %.*s selecting what to print? the out put is a tick mark made of starts:

       *
      *
     *
*   *
 * *
  *

Upvotes: 0

Views: 45

Answers (1)

Harry
Harry

Reputation: 11648

Try this code and it will help explain what's going on...

include <stdio.h>
int main(void) {
    char string[] = "       *      *     **   * * *  *";
    int line = 6, stop = 0, len = 8;
    for(line = 6; line > 0;line--){
        printf("print %d chars starting at position %d\n", len, stop);
        printf("%.*s\n", len, string + stop);
        stop = stop + len;
        --len;
    }   
    return 0;
}

In the printf format ie %.*s the .* means that it is expecting an argument len in your case to specify how many character to print. the string + stop is specifying where to start printing from. I don't know who wrote this piece of code but it's a decent example of setting precision on strings.

Upvotes: 1

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