CODEWITHSUNDEEP
pythonpython-3.xalignmentnumeric
Reman
Reman

Reputation: 8119

How to align numbers by decimal position?

My table: 

  2       4,5   100    400
  3        20    10    100
4,2    10.000   500    600
9,2  10.024,5   610  1.100

mylist = [['2', '4,5', '100', '400'], ['3', '20', '10', '100'], ['4,2', '10.000', '500', '600'], ['9,2', '10.024,5', '610', '1.100']]

How can I align the numbers like this:

2         4,5  100    400
3        20     10    100
4,2  10.000    500    600
9,2  10.024,5  610  1.100

What I did:

for i in range(0, len(mylist)):
    '{:>10} {:>10} {:>10} {:>10}'.format(mylist[i][0], mylist[i][1], mylist[i][2], mylist[i][3])

This gives above results as in the 1st table but the decimals are not aligned.

Update
I adapted the solution of Francisco to the length of the elements in whatever list.

mylist = [['1300', '300', '300'], ['2300,5', '300,5', '300,5'], ['3600000000000', '6000000', '6000000'], ['4200,2345', '200,2345', '200,2345'], ['5301', '301', '301'], ['6200', '200', '200'], ['7300', '300', '300000000'], ['8300,5', '300,500000', '300,5'], ['960000', '600', '6000'], ['10200,2345', '200999,2345', '200,2345'], ['11301', '301', '301'], ['12200', '200', '200'], ['13300', '300', '300'], ['14300,5', '300,5', '300,5']]

column2row = zip(*mylist)
maxbefore = []
maxafter = []
for m in column2row:
    maxlengthbefore = 0
    maxlengthafter  = 0
    for e in m:
        if ',' in e:
           lengthbefore = len(str(e).split(",")[0])
           if lengthbefore > maxlengthbefore:
              maxlengthbefore = lengthbefore
           lengthafter  = len(str(e).split(",")[1])
           if lengthafter > maxlengthafter:
              maxlengthafter = lengthafter
        else:
           lengthbefore = len(str(e))
           if lengthbefore > maxlengthbefore:
              maxlengthbefore = lengthbefore
    maxbefore.append(maxlengthbefore)
    maxafter.append(maxlengthafter + 1)

for m in mylist:
    r = 0
    for e in m:
        if ',' in e:
            print(e.rjust(int(maxbefore[r]) + len(e) - e.index(',')).ljust(int(maxbefore[r])+int(maxafter[r])), end=' ')
        else:
            print(e.rjust(int(maxbefore[r])).ljust(int(maxbefore[r])+int(maxafter[r])), end=' ')
        r += 1
    print()

Output

         1300          300              300      
         2300,5        300,5            300,5    
3600000000000      6000000          6000000      
         4200,2345     200,2345         200,2345 
         5301          301              301      
         6200          200              200      
         7300          300        300000000      
         8300,5        300,500000       300,5    
       960000          600             6000      
        10200,2345  200999,2345         200,2345 
        11301          301              301      
        12200          200              200      
        13300          300              300      
        14300,5        300,5            300,5

Upvotes: 2

Views: 382

Answers (1)

Francisco
Francisco

Reputation: 11496

for m in mylist:
    for e in m:
        if ',' in e:
            print(e.rjust(10 + len(e) - e.index(',')).ljust(15), end=' ')
        else:
            print(e.rjust(10).ljust(15), end=' ')
    print()

prints:

         2               4,5           100             400     
         3              20              10             100     
         4,2        10.000             500             600     
         9,2        10.024,5           610           1.100

Basically what it does is check if the string has a comma in it.

If it does it checks its place, centers the string to the right checking how many characters there are without counting everything after the comma, and then centers it to the left this time counting the places after the comma.

If there aren't commas in the string it just centers it to the left and to the right.

Upvotes: 1

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