Reputation: 1103
I am getting order_by
fields in the form of a list.
I want to order by multiple fields with Django ORM.
List is like below:
orderbyList = ['check-in','check-out','location']
I am writing a query like this:
modelclassinstance.objects.all().order_by(*orderbyList)
Everything I'm expecting in a list is dynamic. I don't have predefined set of data. Could some tell me how to write a Django ORM with this?
Upvotes: 97
Views: 96299
Reputation: 27
modelclassinstance.objects.filter(anyfield='value').order_by('check-in', 'check-out', 'location')
Upvotes: 3
Reputation: 419
You should pass a list of stringified arguments of the database table columns (as specified by your ORM in the respective models.py file) to the .order_by()
method on the return query set like so. shifts = Shift.objects.order_by('start_time', 'employee_first_name')
. By notation,.order_by(**args)
, will help you remember that takes an arbitrary number of arguments.
Upvotes: 0
Reputation: 791
Pass orders list in query parameters
eg : yourdomain/?order=location&order=check-out
default_order = ['check-in'] #default order
order = request.GET.getlist('order', default_order)
modelclassinstance.objects.all().order_by(*orderbyList)
Upvotes: 12
Reputation: 1
What you have to do is chain the querySets, in other words:
classExample.objects.all().order_by(field1).order_by(field2)...
Upvotes: -7
Reputation: 402
Try this:
listOfInstance = modelclassinstance.objects.all()
for askedOrder in orderbyList:
listOfInstance = listOfInstance.order_by(askedOrder)
Upvotes: -3
Reputation: 2586
Try something like this
modelclassinstance.objects.order_by('check-in', 'check-out', 'location')
You don't need .all()
for this
You can also define ordering in your model class
something like
class Meta:
ordering = ['check-in', 'check-out', 'location']
Upvotes: 162